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The standard examples of schemes that are not quasi-compact are either non-noetherian or have an infinite number of irreducible components. It is also easy to find non-separated irreducible examples. But are there other examples?

Question: Let $X$ be a locally noetherian scheme and assume that $X$ is irreducible (or has a finite number of irreducible components) and separated. Is $X$ quasi-compact (i.e., noetherian)?

If the answer is no in general, what conditions on $X$ are sufficient? Locally of finite type over a noetherian base scheme $S$? Fraction field finitely generated over a base? What if $X$ is regular? In general, the question is easily reduced to the case where $X$ is normal and integral.

It certainly feels like the answer is yes when $X$ is locally of finite type over $S$. Idea of proof: Choose an open dense affine $U\subseteq X$, choose a compactification $\overline{U}$ and modify $X$ and $\overline{U}$ such that the gluing $Y=X\cup_U \overline{U}$ is separated. Then, $Y=\overline{U}$ (by density and separatedness) is proper and hence quasi-compact.

Remark 1: If $X\to S$ is a proper morphism, then the irreducible components of the Hilbert scheme Hilb(X/S) are proper. The subtle point (in the non-projective case) is the quasi-compactness of the components (which can be proven by a similar trick as outlined above).

Remark 2: If $X\to S$ is universally closed, then $X\to S$ is quasi-compact. This is question 23337.

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Excellent example. My intuition was clearly wrong (perhaps due to the Hilbert-example). Is it possible to move your comment to an answer so I can accept it? –  David Rydh Aug 5 '10 at 15:42
Dear David, Brian's example is indeed the standard one, and obviously works in any dimension $\geq 2$. In the one dimensional case, on the other hand, one can prove that locally Noetherian, irreducible, and separated implies quasi-compact. (I don't think I'm missing any other hypotheses.) –  Emerton Aug 5 '10 at 15:57
Dear David: OK, I have promoted my comment to an answer. I didn't know about the abstract 1-dimensional result which Emerton mentioned. –  BCnrd Aug 5 '10 at 17:03
Dear Brian and David, Looking at Qing Liu's answer below, I realized that I probably did miss a hypothesis! In fact (having thought some more), what I think is true is the (somewhat less surprising) statement that locally finite type over a field, irred., one-dimensional, and separated implies quasi-compact. (Note that this still has some relevance to Brian's example, which is locally of finite type over a field.) –  Emerton Aug 5 '10 at 18:11
Yes, one can replace a field by any noetherian excellent scheme $S$, the proof is the same: one can suppose $X$ is normal. Let $U$ be an affine open subset of finite type over $S$. Then $U$ has a compactification $\bar{U}$ which is projective over $S$ and normal (use once again that $S$ is excellent). The inclusion $U\to \bar{U}$ then extends to a morphism $X\to \bar{U}$ by valuative criterion of properness. This morphism is injective because $X$ is separated (two points having the same image have the same local ring). So $X\setminus U$ is finite and $X$ is quasi-compact. –  Qing Liu Aug 5 '10 at 19:34
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4 Answers

up vote 15 down vote accepted

There are smooth counterexamples. Let $S_0$ be a smooth separated irreducible scheme over a field $k$ with dimension $d > 1$, and $s_0 \in S_0(k)$. Blow up $s_0$ to get another such scheme $S_1$ with a $\mathbf{P}^{d-1}_k$ over $s_0$. Blow up a $k$-point $s_1$ over $s_0$ to get $S_2$, and keep going. Get pairs $(S_n, s_n)$ so that the open complement $U_n$ of $s_n$ in $S_n$ is open in $U_ {n+1}$ and is strictly contained in it. Glue them together in the evident manner, to get a smooth irreducible $k$-scheme. It is locally of finite type, but is not quasi-compact (since the $U_n$ are an open cover with no finite subcover). This is separated (either by direct consideration of affine open overlaps, or by using the valuative criterion).

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I had in mind the example of a separated, locally noetherian, irreducible regular scheme of dimension 1 which is not quasi-compact, I hope it is correct: let $X$ be a separated integral (locally) noetherian scheme of dimension $\ge 1$ such that the set $F$ of the points of codimension 1 in $X$ is infinite ($X$ could be the affine line over a field). Let $\xi$ be the generic point of $X$ and $K(X)=O_{X,\xi}$. We construct a new scheme $X'$ by gluing all the $U_x:={\mathrm Spec} (O_{X,x})$, $x\in F$, along $\xi$. Then $X'$ is locally noetherian regular of dimension $1$ (because $U_x$ is the the spectrum of a DVR), irreducible because $\xi$ is the unique generic point, and separated because the canonical map $O_{X,x}\otimes O_{X, y}\to K(X)$ is surjective if $x\ne y \in F$. But $X'$ is not quasi-compact because the covering { $U_x$ }$_{x\in F}$ can not be refined by a finite covering.

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Cool. OK, so now I wonder what hypothesis Matt may have forgotten from a result in the 1-dimensional case. Maybe locally finite type over a noetherian domain (or field)? –  BCnrd Aug 5 '10 at 18:08
Dear Qing Liu, a very nice example! Dear Brian, Exacly! (See my new comment at the top of the question.) –  Emerton Aug 5 '10 at 18:11
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This is just an elaboration on BCnrd's example to illustrate that it is in no way pathological but rather appears very naturally.

To begin with we can let the starting variety be $\mathbb P^1\times\mathbb P^1$. This is a toric variety described by the fan in $\mathbb R^2$ given by the four quadrants (and the lattice is $\mathbb Z^2$). The blowing up of $(0,0)$ corresponds to adding the halfline through $(1,1)$ (and the cones on either side). Then blowing $0$ up $(0\colon1)$ on the exceptional curve corresponds to adding the halfline through $(2,1)$. Continuing in this way corresponds to adding the halflines through $(n,1)$ and passing to the limit gives the fan consisting the three quadrant and the fans spanned by $(n,1)$ and $(n+1,1)$ for $n\ge 0$. Concretely the affine toric variety corresponding to the fan spanned by $(n,1)$ and $(n+1,1)$ has affine algebra generated $r_i=xy{-i}$ and $s_i=x^{-1}y^{i+1}$ and (where $x$ and $y$ are generators for the coordinate ring of the torus). Note that we have $r_is_i=y$ a relation in terms of one of the coordinates as well as $r_{i+1}s_{i}=1$.

We may make the construction more symmetric by blowing up also the points at $\infty$ of the exceptional divisors. This corresponds to adding the halflines through $(1,n)$ and for the affine rings letting $i$ run over all integers. This construction then works over a discrete valution ring $R$ with generator (say) $\pi$. We then put $r_is_i=\pi$ and embed the ring generated by it into $K[x,x^{-1}]$ by mapping $r_i=x\pi^{-i}$ and $s_ix^{-1}\pi^{i+1}$. This gives a scheme locally of finite type over $\mathrm{Spec}R$ whose generic fibre is $\mathbb P^1_K$ and whose special fibre is an infinite line of $\mathbb P^1$'s (the $(0\colon1)$ identified with $(1\colon0)$ of the next). We have an autormorphism $\varphi$ of this scheme taking $r_i\mapsto r_{i+1}$ and $s_i\mapsto s_{i+1}$ which on the generic fibre takes $x$ to $x\pi^{-1}$. It shifts the $\mathbb P^1$'s. We can now consider the formal completion with respect to the closed point of $\mathrm{Spec}R$. On it $\varphi$ acts properly continuosly so we may construct the quotient. The resulting formal scheme is proper and can be algebraised (when $R$ is complete). The resulting scheme is the Tate curve.

A more invariant way of constructing fan is to consider the convex hull of the lattice points of the open first quadrant and then draw halflines through the lattice points at the boundary of this hull. As these points are exactly the $(1,n)$ and $(n,1)$ we get the previous example. We can do the same thing in the following situation: We let $K$ be a real quadratic field, let the cone $C$ be spanned by the totally positive elements of $K$ and let the lattice be the algebraic numbers of $K$. We can then construct the fan by adding halflines through the lattice points on the boundary of the convex hull which gives us a toric scheme locally of finite type. The totally positive units of $K$ acts on this fan and we may take the quotient of the formal completion as before. This gives a resolution of a (particular) cusp of the Hilbert modular surface associated to $K$ (see for instance Oda: Convex bodies and algebraic geometry).

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Actually, Nick Proudfoot and I have been talking for years about the irreducible smooth surface constructed from countably many copies of ${\mathbb A}^2$ by gluing $(p,q)$ in the $n$th copy to $(p^2q,p^{-1})$ in the $n+1$th copy. This even has a ${\mathbb G}_m$ action $\lambda \cdot (p,q) = (\lambda p, \lambda^{-1} q)$, a symplectic form $dp \wedge dq$, and a moment map $(p,q) \mapsto pq$ whose zero fiber is an infinite chain of projective lines. This too can be regarded as the toric variety associated to a fan of infinite type in the plane. It appears to be another way of describing Ekedahl's example.

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