# Is the ability to define Haar measure the main (or only) reason to consider locally compact topological groups? [closed]

Because I haven't seen locally compact topological groups used for anything except Fourier analysis.

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## closed as not a real question by Harry Gindi, François G. Dorais♦, Robin Chapman, Gjergji Zaimi, S. Carnahan♦Jun 2 '10 at 2:39

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A lot of examples of topological groups in the "real world" are locally compact, for instance Lie groups, groups of ideles and adeles etc. And Fourier analysis is a powerful technique for these; see Tate's thesis. Non-commutative analogues lead to the wonders of the Langlands programme etc. – Robin Chapman May 31 '10 at 10:29
Closed. Try phrasing your questions more tactfully, and with more context. See the "how to ask" page for tips. – S. Carnahan Jun 2 '10 at 2:42

I can think of two ways to answer this question.

First, regarding your comment "I haven't seen locally compact topological groups used for anything except Fourier analysis," I think the appropriate answer is given by Charles Matthews and Robin Chapman. Locally compact topological groups "arise in nature". Here's a general theorem explaining how -- a more general statement and proof can be found in Brian Conrad's notes (PDF file).

Let $A$ be a local topological ring, such that $A^\times$ is open in $A$ and has continuous inversion. If $A$ is locally compact and Hausdorff, and $G$ is a algebraic group (separated group scheme locally of finite type suffices) over $A$, then $G(A)$ is a locally compact Hausdorff topological group.

This implies that $GL_n(A)$ is locally compact, for a wide class of important rings $A$. Conrad's notes also explain how this can be extended, under some hypotheses, to the adelic points of algebraic groups (following Weil).

A second way to answer your question is the following: if one cares about harmonic analysis on groups, then the setting of locally compact topological groups is precisely the right setting to work in. Besides the existence of Haar measure, an important converse is given in an appendix to Weil's "L'intégration dans les groupes topologiques et ses applications." I refer to Weil's result that -- given a group $G$ with a left-invariant measure $\mu$, satisfying an additional very general condition or two (one condition is that if $f$ is a measurable function on $G$, then $(x,y) \mapsto f(x^{-1} y)$ is a measurable function on $G \times G$), there is a unique topology on $G$ for which its completion $\hat G$ is locally compact and has Haar measure equal to the natural extension of $\mu$. In other words, not only is the "locally compact" condition sufficient for existence of Haar measure, but it is a necessary condition for anything resembling Haar measure to exist.

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"Locally compact", for example, forces a Banach space to have a finite dimension. Restricting to locally compact groups excludes many "big" examples, and keeps many useful ones, such as adele groups in number theory. It includes Lie groups. It is a sensible class in which to work out representation theory, including non-commutative analogues of Pontryagin duality (Fourier theory).

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An example of relevance of the local compactness is given by the Chabauty topology: it is a natural topology defined on the set $C(G)$ of closed subgroups of a topological group $G$. When $G$ is locally compact, then $C(G)$ is compact (and can be used for example to construct compactifications). To learn more one this, Pierre de la Harpe has written a nice survey (on arxiv and his web page, I guess).

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On the arXiv and on the web page. – L Spice Oct 16 '15 at 3:47