4
$\begingroup$

Suppose it is given an orientation preserving homotopy equivalence $h:N→M$ between closed oriented connected manifolds. Let $X,Y\subset M$ be diffeomorphic submanifolds, and assume $h$ to be transverse to both $X$ and $Y$. Define $A:=h^{−1}(X)$ and $B:=h^{−1}(Y)$. I would like to know if

sign($A$)=sign($B$) ?

To avoid triviality, assume dim($A$)=dim($B$) to be a multiple of 4. Is there a way to show that (maybe) $A$ and $B$ are oriented cobordant? Any example/counterexample can be useful.

$\endgroup$
2
  • 1
    $\begingroup$ What do you mean exactly by $h$ being transverse to $X$ and $Y$? $\endgroup$ Oct 8, 2015 at 20:25
  • $\begingroup$ I am assuming $h$ to be smooth, like everything else here. Therefore it makes sense to speak of transversality ($dh_a(T_aN)+T_{x}X=T_{x}M$ for every $a\in h^{-1}(x)$). This is the condition which ensures $A$ and $B$ to be closed smooth manifolds. $\endgroup$ Oct 9, 2015 at 8:46

1 Answer 1

2
$\begingroup$

This turned out to be false. By Example 3.1 in the paper of James Davis "Manifold aspects of the Novikov conjecture", there is a homotopy equivalence $h:S(E')\to S^4\times S^4$ such that $\sigma(h^{-1}(pt\times S^4))=16$, but $\sigma(h^{-1}(S^4\times pt))=\sigma(S^4)=0$ since $h$ preserves the fibers.

$\endgroup$
2
  • $\begingroup$ More simply, take any example of a homotopy equivalence $h:N\to M$ such that some sphere $A\subset M$ has $\sigma(h^{-1}(A))\neq 0$, and choose $B$ to be a sphere in $M$ of the same dimension as $A$ that bounds a disk in a coordinate chart of $M$. $\endgroup$ Nov 13, 2015 at 17:53
  • $\begingroup$ It sounds correct, clearly. But I wasn't able to find such a concrete example, since the map $h$ should not have the homotopy type of a homeomorpshim and hence it is not immediate (at least for me) to deal with these manifolds. $\endgroup$ Nov 13, 2015 at 18:01

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.