0
$\begingroup$

Let $W(n,m)$ be generalized Jacobson-Witt algebra over a field of characteristic $p>3$. According to the grading of $W(n,m)$, we know that it inherits the grading from $A(n,m)$ as follows: $$W(n,m)_i=\sum_{j=1}^{n} A(n,m)_{i+1}D_j\;.$$ Consequently, $$W(n,m)=\bigoplus_{i=-1}^{s} W(n,m)_{i}$$ with $ s=\sum_ {i=1}^{n} (p^{m_i}-1)-1$. I want to know the reason of writing the index of $A(n,m)$ in $W(n,m)_i=\sum_{j=1}^{n} A(n,m)_{i+1}D_j$ ? in fact why we must put $i+1$ ? In the case of $p=2$ how is the grading for $W(n,m)$?

$\endgroup$
2
  • 2
    $\begingroup$ because the $D_j$ lower degree by one $\endgroup$ Jan 31, 2015 at 5:33
  • $\begingroup$ it means that $D_j$ acts on $A(n,m)_{i+1}$ from left? sorry I am confused of that? $\endgroup$
    – user118746
    Jan 31, 2015 at 13:12

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.