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Each orientable 3-manifold can be obtained by doing surgery along a framed link in the 3-sphere. Kirby's theorem says that two framed links give homeomorphic manifolds if and only if they are obtained from one another by a sequence of isotopies and Kirby moves.

The original proof by R. Kirby (Inv Math 45, 35-56) uses Morse theory on 5-manifolds and is quite involved. There are two simpler proofs that use Wajnryb's presentations of mapping class groups. One is due to N. Lu (Transactions AMS 331, 143-156) and the other to S. Matveev and M. Polyak (Comm Math Phys 160, 537-556). I would like to ask what other proofs of Kirby's theorem are known. In particular, is there a proof that uses only Morse theory/handle decompositions of 3-manifolds?

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Note that Daniel Moskovich did apparently scan in the 1974 preprint and is asking whether you can "accept" his answer. –  Will Jagy May 3 '10 at 18:22
    
Will -- done. In fact, it has been a while since I last looked at this question. –  algori May 3 '10 at 21:50
    
Thanks for taking care of that. –  Will Jagy May 4 '10 at 1:11

2 Answers 2

up vote 17 down vote accepted

There is Bob Craggs' 1974 proof, which was never published. It relies on Wall's result, that any two 2-handle cobordisms between S^3 and itself are stably homeomorphic if the associated bilinear forms have the same signature and type. It's very much what you are after. I have a hard-copy in my office. I do not fully follow all aspects of the argument and therefore cannot yet vouch for it. I uploaded a scan of his preprint HERE (thanks Ryan for help combining PDF files!).
I'm not positive which proof (Cerf theory or MCG) is really "simpler", because both proofs rely on a lot of background "black boxes". For Kirby's proof, later simplified by Fenn and Rourke, and then later by Justin Roberts, the only black box is Cerf's theorem. Surely the proof of Cerf's theorem could be tremendously simplified, and after this is eventually done by somebody, my money would be on the Cerf theory proof to be slicker. The MCG proof uses presentations of the mapping class group, which use simple connectedness of the Hatcher-Thurston complex (itself not so easy to prove), and results on buildings (a result of Brown) in order to construct presentations of the group from its action on a simply connected simplicial complex. This is actually a lot of machinery, if you think about it. Again, you can simplify the proof by using Gervais's presentation, proven directly by Silvia Benvenuti using an ordered complex of curves or by Susumu Hirose using a complex of non-separating curves.
When all is said and done, I am personally not satisfied with any of the proofs out there. The Cerf theory proof, while being conceptual, takes you into deep and hard analytic terrain- while there is nothing at all conceptual about the MCG proof, despite it being "easy" (it's definitely much easier than Cerf theory, at least for me). The heart of the proof is to check that it happens to be possible to realize "relations" in your favourite finite presentation of the MCG by Kirby moves on links which generate the Dehn twists. The presentation itself is almost incidental, and the relations don't represent Kirby moves in any obvious way (the proof only goes one way- you could not prove a finite presentation of the MCG from Kirby's theorem).

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Thanks, Daniel! Is there a chance you could scan the 1974 preprint? Just out of curiosity: why wasn't it published? –  algori Mar 2 '10 at 17:33
    
Sorry for being pushy, but if you think my answer is OK, I'd be happy if you could except it (that being the currency on MO). –  Daniel Moskovich May 2 '10 at 16:05
1  
@Daniel, perhaps you mean "accept it" And, in the event that Algori has not looked at this since March 2, I note that your first paragraph has a link to the 1974 Bob Cragg preprint. But on a technical note: I believe algori is notified by MO if you put a comment directly after a question or answer posted by algori, but not if your comment is directly after your own question or answer. –  Will Jagy May 3 '10 at 18:24
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@Daniel: also, now that I think of it, I am not sure algori would have been notified on March 15 when you edited your answer. I have not asked enough questions to be sure about that. It is still true that an edited answer (but not a new comment) moves a question to the front of the "active questions" ordering. I chanced on the idea of putting a comment after a Wadim Zudilin answer, then he would put his reply after an answer of mine, and so on. Workable in the short run for a one-to-one conversation. Partly needed due to the huge time zone difference, although email is an option with me. –  Will Jagy May 3 '10 at 18:36
    
The link to the preprint seems to be dead now. –  j.c. Dec 9 at 15:58

The first reference attempts to solve this problem but only gives a partial answer. The second reference shows that every 3-manifold can be obtained by surgery on a link (but does not discuss Kirby calculus).

MR1075370 (91k:57019) Rêgo, Eduardo ; de Sá, Eugénia César . Special Heegaard diagrams and the Kirby calculus. Topology Appl. 37 (1990), no. 1, 11--24.

MR0809959 (87f:57016) Rourke, Colin . A new proof that $\Omega_3$ is zero. J. London Math. Soc. (2) 31 (1985), no. 2, 373--376.

I apologise if you are already aware of these references.

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Thanks, Bruce! I've edited the posting so that the formula is now shown correctly. –  algori Mar 2 '10 at 12:31

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