6
$\begingroup$

An element of the tangent bundle $T M$ of a manifold is called a "(tangent) vector". An element of its dual $T^* M$ is called a "covector" or a "1-form". An element of the exterior square $\Lambda^2(T M)$ is called a "bivector", and an element of $\Lambda^2(T^*M)$ is called a "2-form". More generally, elements of the various tensor powers of $T M$ and $T^*M$ are called "tensors".

Is there a name for an element of an iterated tangent bundle $T^k M = T(T(\cdots (T M)))$?

$\endgroup$
12
  • $\begingroup$ I'd call them something like "n-fold variations". $\endgroup$ May 21, 2014 at 5:55
  • 5
    $\begingroup$ Shouldn't we reserve $1$-form to mean a global section of $T^{\ast}$ rather than a point in its total space? $\endgroup$ May 21, 2014 at 6:01
  • 2
    $\begingroup$ @Qiaochu: people already use the term 1-form for elements of a dual vector space, so global section or not, the terminology is in use. And Paul: what's the distinction between higher-order and iterated tangent bundles? $\endgroup$ May 21, 2014 at 6:41
  • 1
    $\begingroup$ @PaulReynolds is the second order tangent bundle really a vector bundle? I thought that it wasn't (even though each fiber is a vector space) since jets don't transform like vectors. $\endgroup$ May 21, 2014 at 13:04
  • 2
    $\begingroup$ FWIW, if we have to invent a name, the best I've thought of so far is "flare" -- like a jet, but less unidirectional. $\endgroup$ May 21, 2014 at 13:58

1 Answer 1

5
$\begingroup$

I called them "expansion" because they act on functions on $M$ by (Taylor) expanding them. This is a generalization of derivation. See 37.6 of

  • Ivan Kolár, Jan Slovák, Peter W. Michor: Natural operations in differential geometry. Springer-Verlag, Berlin, Heidelberg, New York, (1993) pdf.

Perhaps you need to skim the whole chapter VIII.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.