MathOverflow is a question and answer site for professional mathematicians. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Recall the definition of the representation ring $R(G)$ of a compact Lie group $G$. I'd like a reference that gives me basic ring-theoretic properties that $R(G)$ always has, or enough info that I can check for various properties myself.

share|cite|improve this question
What about structure? $R(G)$ is always a $\lambda$-ring, although it has even more structure than this, e.g. it's acted on by all Schur functors. – Qiaochu Yuan Feb 9 '14 at 23:10
I'm thinking things like Noetherian, Henselian, finite (whatever) dimension, etc. The sorts of things that come up in vanilla commutative algebra. – David Roberts Feb 9 '14 at 23:24
As the answer you've accepted indicates, $R(G)$ is pretty boring as a ring; I think the proper point of view on it is as a ring-with-basis. (And then it's very interesting.) – Allen Knutson Feb 11 '14 at 4:49
up vote 13 down vote accepted

Assume that $G$ is connected. Let $T$ be a maximal torus of $G$. Restriction induces a map $R(G) \to R(T)$. Note that $R(T)$ is a Laurent polynomial ring in $r$ variables where $r$ is the rank. Because the conjugates of $T$ fill up $G$, Peter-Weyl implies that this map is injective. Moreover, if $W$ is the Weyl group, then the image of this map lies in $R(T)^W$, and I think this map is always an isomorphism. So $R(G)$ is about as nice as possible: in particular, it is a finitely generated integral domain, so Noetherian of finite Krull dimension, etc. A lot is known about invariants of Weyl groups so you can probably get even more explicit information than this.

Example. Let $G = \text{U}(n)$. Then $R(T)$ is a Laurent polynomial ring in $n$ variables, the Weyl group is $W \cong S_n$ acting by permutation, and the invariant subring is $\mathbb{Z}[e_1, ..., e_n, e_n^{-1}]$ where $e_i$ is the $i^{th}$ elementary symmetric polynomial, which corresponds to $\Lambda^i(\mathbb{C}^n)$.

share|cite|improve this answer
Note that a good reference for the structure of representation rings is section VI.2 of Springer GTM 98 Representations of Compact Lie Groups by Brocker and tom Dieck. In particular, the ring is finitely generated (hence noetherian) and has more precise properties if $G$ is simply connected, etc. – Jim Humphreys Feb 10 '14 at 0:15
@Jim: thanks for the reference! My claim above is Proposition 2.1 in that section, and the more precise information when $G$ is simply connected is Corollary 2.11. In this case $R(G)$ is actually the polynomial ring on $r$ variables where $r$ is the rank. – Qiaochu Yuan Feb 10 '14 at 0:56
In fact, I just found that Segal proved $R(G)$ is finitely generated for any compact $G$, by using finite generation over $R(U(n))$. – David Roberts Feb 10 '14 at 4:23
@David: I should have added an online link to Segal's 1968 paper: (which Serre discusses in the finite group case, in his textbook on finite group representations). – Jim Humphreys Feb 10 '14 at 13:11

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.