1

I am new to semigroup research, so I apologize if this is an easy question.

flag

1 Answer

13

Assuming by M(n, Z) you mean the semigroup (monoid) of n × n matrices over the integers under multiplication: no, it is not even finitely generated, because the determinant M(n, Z) → Z is multiplicative (Z denoting the monoid of integers under multiplication) and Z is not finitely generated (by the infinitude of primes).

link|flag
3 
If n=0, then M(n,Z) is finitely presented! (Sorry for being obnoxious.) – Bjorn Poonen Feb 10 2010 at 8:33

Your Answer

Get an OpenID
or

Not the answer you're looking for? Browse other questions tagged or ask your own question.