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Are there known examples of compact infinite dimensional manifolds?

The word "manifold" is important.

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closed as unclear what you're asking by BS., Andrey Rekalo, Carlo Beenakker, Ricardo Andrade, David White Oct 25 '13 at 12:44

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How do you define an infinite dimensional manifold? Is it modelled on the countable product of lines? – Igor Belegradek Oct 25 '13 at 0:56
If this is your definition, then the answer is no, because if $K$ is a compact subset of a manifold $Y$ modelled on the countable product of lines, then $Y$ and $Y-K$ are homeomorphic. – Igor Belegradek Oct 25 '13 at 1:04
just modelled on a vector space. like Banach manifold, Frechet manifold. – user8991 Oct 25 '13 at 1:07
Any separable Frechet (or Banach) space is homeomorphic to the countable product of lines, so my answer above applies. – Igor Belegradek Oct 25 '13 at 1:18
It seems to me Pietro Majer already addressed this in his answer here: Right? – Todd Trimble Oct 25 '13 at 2:01
up vote 8 down vote accepted

The empty space is a manifold of any dimension.

No, seriously, let's assume that "manifold" means a Hausdorff space in which every point has an open neighborhood homeomorphic to an open subset of a topological vector space. If the manifold is compact and nonempty then the vector space must be locally compact. As far as I know, that makes it finite-dimensional.

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Feeling of deja vu... Ah yes: – Todd Trimble Oct 25 '13 at 1:38

Yes. Compact Hilbert cube manifolds, for instance.

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wrong. the Hilbert cube is not a manifold… – user8991 Oct 25 '13 at 1:06
perhaps you mean it is not a differentiable manifold. – johndoe Oct 25 '13 at 1:09

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