The prime number theorem tells us that , if $\pi\left(x\right)$ denotes the number of primes less than or equal to $x$, we have $$\pi\left(x\right)\sim\frac{x}{\log x}.$$ In a similar manner considered $1\leq a \leq q$ with $(a,q)=1$ and defined $\pi\left(x,a,q\right)$ the number of primes less than or equal to $x$ congruous $a\,\textrm{mod}\, q$ and $\phi\left(n\right)$ the number of minor numbers and coprime with $n$, we have $$\pi(x,a,q)\thicksim\frac{1}{\phi(q)}\frac{x}{\log x}.$$ If $q$ is "small" you have asymptotic formulas for $\pi\left(x,a,q\right)$ (see the Siegel  Walfisz theorem). For any $q$ we have the estimate $$\pi(x,a,q)\gg\frac{1}{\phi(q)}\frac{x}{\log x}.$$ I would like to know if there is an estimate of the type $$\pi(x,a,q)\ll\frac{1}{\phi(q)}\frac{x}{\log x}$$ for any $q$. I hope I was clear! Sorry for my bad english!

For $x\leq\phi(q)$ the estimate $\pi(x,a,q)\ll\frac{1}{\phi(q)}\frac{x}{\log x}$ would imply $\pi(x,a,q)\ll\frac{1}{\log x}$, i.e. $\pi(x,a,q)=0$ for large $x$ which is clearly false. So a bound you envision can only hold for $x$ slightly above $\phi(q)$. On the other hand, for any $\epsilon>0$, the BrunTitchmarsh inequality implies $$\pi(x,a,q)\ll_\epsilon\frac{1}{\phi(q)}\frac{x}{\log x},\qquad x>q^{1+\epsilon}.$$ 


Siegel  Walfisz theorem states $$\psi(x,q;a)=x/\phi(q)+O(x/\log^Ax)$$when q is small;q is big ,the results is trival . (When is the SiegelWalfisz theorem nontrivial?) if $q \ll log^Ax$,we have $$\sum_{x\equiv 1 \bmod q } \Lambda(n)\ge (1\epsilon) x/\varphi(q).$$ (Prime numbers in arithmetic progressions : uniformity with respect to the modulus ) I think q is big, there is no the $\ll$ results as you asked. Since when q is big ,there may be existing Siegelzeros, then there exist constants 0 < β−, β+ < 1 such that $x^{\beta_{}}/\beta_{}\ll x\phi(q)\pi(x,q;a) \log x \ll x^{\beta}_{+}/ \beta _{+}$. (see section 3 , and http://www.dms.umontreal.ca/~andrew/PDF/ItalySurvey.pdf) or see Theorem (SiegelWalfisz with a twist). in (Chebychev Function in Arithmetic Progressions ) 

