Everyone knows that analytic functions $f_1,\ldots,f_n$ are linearly dependent if and only if their Wronski determinant is identically equal to zero. There are several proofs of this, one in Polya-Szego, vol. 2 Ch. 7, probl. 60.

Is this result stable? More precisely, is the following true:

For every $\epsilon>0$ there exists $\delta>0$ with this property: if analytic functions $f_1,\ldots,f_n$ in the unit disc satisfy $|W(f_1,\ldots,f_n)(z)|<\delta \| f\|^n$ for $|z|<1$, then there exists a unit vector $a=(a_1,\ldots,a_n)$ such that $|a_1f_1+\ldots+a_nf_n|<\epsilon\| f\|$ for $|z|<1/2$. Here $\| f\|=\sqrt{|f_1|^2+\ldots+|f_n|^2}$.

If this is true, I would like to know something about $\delta$ as a function of $\epsilon$. This is easy to prove when $n=2$ with $\delta\approx\epsilon$. It is also easy to prove for formal power series that if the Wronskian is small in "p-adic norm", then there is a linear combination that is small in "p-adic norm". I can also prove the converse statement for every $n$: if the functions are almost linearly dependent, then their Wronskian is small.

EDIT. I would be glad to see any other statement meaning that "if the Wronskian is small, then there is a linear combination which is small".