Take the 2-minute tour ×
MathOverflow is a question and answer site for professional mathematicians. It's 100% free, no registration required.

Let in the complex plane be a bounded Jordan region T (that is a bounded and simply connected set with the boundary a Jordan curve), containing the origin, with its Riemann mapping onto the open unit disk, having in its Taylor expansion all the coefficients as real numbers.

Question : There exists a sequences of strictly decreasing (in the sense of set inclusion) and converging to T, Jordan domains T_{n} (including strictly T), so that their corresponding Riemann mappings, f_{n}, converge uniformly in the closure of T, to the Riemann mapping f and in addition, all f_{n} having their Taylor expansions with real coefficients ?

Remark. In the case when we do not require that the coefficients in the Taylor expansions of the Riemann mappings be all real numbers, the answer to the above questions is YES, see e.g. Theorem 4, p. 32, in the J.L. Walsh's book-"Interpolation and Approximation by Rational Functions in the Complex Domain."

share|improve this question
    
Remark 2. To be very precise, because above we talk about Taylor series, the Question one refers in fact to the inverses of the Riemann mappings, f^{-1} and f_{n}^{_1} (which are defined on the open unit disk). But the Question can remain in the initial form without to produce too much confusion I think, because the uniform convergence of f_{n} to f is equivalent to the uniform convergence of f_{n}^{-1} to f^{-1} and if f_{n}^{-1} and f^{-1} have their Taylor series with all the coefficients real, then clearly f_{n} and f have their Laurent series expansions Laurent with all the coeff. real. –  George May 27 '13 at 11:11

1 Answer 1

A holomorphic function $f$ has a Taylor series with real coefficients if and only if it is symmetric with respect to the real line, i.e. satisfies $f(\bar z)=\overline{f(z)}$. Let's call such functions real maps.

If the Riemann map $f$ is a real map, then $T=f^{-1}(\mathbb D)$ is symmetric with respect to the real line. The converse is also true by uniqueness of a Riemann map with $f(0)=0$ and $f'(0)>0$.

The question thus reduces to finding a sequence of symmetric Jordan domains $T_n$ decreasing to the closure of $T$, for then the Riemann maps $f_n$ (which are then real maps) converge to $f$ locally uniformly by Carathéodory kernel theorem.

You can take for example $T_n := \mathbb C \setminus g(\overline{\mathbb{D}}(0,1-2^{-n}))$ where $g$ is the Riemann map from the unit disk to $\widehat{\mathbb{C}}\setminus \overline T$, with a simple pole of positive residue at the origin.

share|improve this answer
    
Welcome to MO, Maxime Fortier Bourque! –  Malik Younsi May 27 '13 at 13:29
    
Many thanks Maxime. I'm just writing a joint research paper and this was a missing point in a proof of a result. Once finished the paper, I will mention your name in an acknowledgement and then will send you the PDF file of the paper. Best, G –  George May 27 '13 at 15:44

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.