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Let $G$ be a complex Lie group (not necessarily connected) with reductive Lie algebra $\frak{g}$. (We may assume that $G$ has finitely many connected components and is linear-algebraic.) Of course, $G$ need not be the complexification of a compact Lie group (ex. $G=\mathbb{C}$). To what extent, however, is $G$ "close" to being the complexification of a compact Lie group? Does $G$ belong to some kind of extension involving the complexification of a compact Lie group? Is $G$ some reasonably nice quotient of the complexification of a compact Lie group? I would appreciate any answers to questions of this nature. Also, I would appreciate any and all references.

Thanks!

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The functor $G \rightarrow G(\mathbf{C})$ is an equivalence from linear algebraic $\mathbf{C}$-groups $G$ with reductive $G^0$ to complex Lie groups $H$ with reductive Lie algebra and finite $\pi_0(H)$ such that $Z_{H^0}$ is a power of $\mathbf{C}^{\times}$. For any such $H$ and maximal compact subgroup $K$, denote by $K'$ the unique linear algebraic $\mathbf{R}$-group with $K'(\mathbf{R})=K$ meeting every component of $K'$. Then $K'(\mathbf{C})=H$ and $H$ is the complexification of $K'$ as defined in Bourbaki. See D.3.2 and D.3.3 in the Luminy notes on reductive group schemes (use Google). –  user28172 Mar 20 '13 at 15:08
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@PDC: The expression reductive Lie group in the header already raises questions about how you would define this notion. For linear algebraic groups the concept depends on the Jordan decomposition rather than the Lie algebra. Your 1-dimensional example shows the complication here, while your earlier question is relevant: mathoverflow.net/questions/124418 –  Jim Humphreys Mar 20 '13 at 20:31
    
Correction to my previous comment: I should have written $Z^0_{H^0}$ rather than $Z_{H^0}$. –  user28172 Mar 20 '13 at 20:42
    
These are good points. For me, the relevant notion of reductivity for complex Lie groups is that of linear reductivity (or equivalently, being the complexification of a compact Lie group). Is the issue with example $G=\mathbb{C}$ in some sense the only way that $G$ can fail to be the complexification of a compact Lie group? Are there any structure theorems for complex Lie groups $G$ with reductive Lie algebras that relate such groups $G$ to linearly reductive groups? –  Peter Crooks Mar 20 '13 at 20:53
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@PDC: There are commutative compact complex Lie groups which have nothing to do with linear algebraic groups, namely the "complex tori" in the sense of $V/L$ for a finite-dimensional complex vector space $V$ and full rank lattice $L$ in $V$. So the structure of the center needs to be brought out in the analytic theory to "rule out" problematic cases. The description I gave with the Lie algebra and the center (and a bit for the component group) seems as "good" as one can hope to say over $\mathbf{C}$ (life is harder over $\mathbf{R}$), or maybe someone else has a better idea... –  user28172 Mar 20 '13 at 23:46
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