Let $\mathfrak{g}=< X_{f_1},X_{f_2},...,X_{f_n}> $ be a lie algebra of contact symmetries , $\mathfrak{g}\subset Sym(E_\omega )$ , such that the orbit spact $ B_\mathfrak{g}=E_\mathfrak{g}/ \mathfrak{g}$ is smooth Then can we say $(B_\mathfrak{g}, C_\mathfrak{g}, \omega_\mathfrak{g})$ is contact manifold? where if $\pi :E_\mathfrak{g}\rightarrow B_\mathfrak{g}$ be the natural projection and $C_\mathfrak{g}([a])=\pi_*(C_\mathfrak{a}\cap T_a E_\mathfrak{g})$ and $[a]$ is orbit of $a\in E_\mathfrak{g}$ and $\omega_{\mathfrak{g}}=i_{X_{f_1}}\circ i_{X_{f_2}}\circ ...i_{X_{f_k}}(\omega)$ .Here $\omega\in \Omega^n(J^1M)$, and by sense of V.Lychagin we denote the monge ampere equation $\Delta_\omega=0$ by $E_\omega$ . Moreover $E_{\mathfrak{g}}$ is the set of solutions of $(f_1=0,f_2=0,....,f_k=0 )$ . .You can find this fact as theorem 12.3.1 link text page 258 In fact in this book the authors used of this fact and never proved it
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