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Let $f$ be a non-identically zero bounded analytic function in the open unit disk $\mathbb{D}$. It is well-known that $f$ has radial limits almost everywhere on the unit circle $\mathbb{T}$. Let $Z_f$ be the set of points in $\mathbb{T}$ where $f$ has zero radial limit :

$$Z_f:= \{e^{i\theta} \in \mathbb{T} : \lim_{r \rightarrow 1}f(re^{i\theta})=0\}.$$

Then it is also well-known that $Z_f$ has measure zero.

My question is the following :

For which sets $E \subseteq \mathbb{T}$ of measure zero does there exist a bounded analytic function $f$ in $\mathbb{D}$ such that $E=Z_f$?

Remark : It is easy to see that every $Z_f$ is a $F_{\sigma \delta}$, so the question could be wether or not every $F_{\sigma \delta}$ of measure zero is $Z_f$ for some $f$.

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I'm having some problem with LaTex in the definition of $Z_f$... Does someone know how to fix that? – Kalim Mar 10 '13 at 12:17
From "How to write math" (look on the right $\rightarrow$): if you're having problems with the preview (or the post looks wrong), put backticks around any math that contains underscores or asterisks. E.g. write $f'_n=g_{n+1}$. – Giuseppe Mar 10 '13 at 12:25
@Giuseppe : Thank you! – Kalim Mar 12 '13 at 20:20

Lohwater and Piranian proved that for every set $F_\sigma$ of measure zero, there exists a bounded analytic function which has radial limits exactly on the complement of this set. (Ann. Acad. Sci. fenn., 239 (1957) 1-17.)

In the book of Collingwood and Lohwater, Theory of cluster sets (1966) they say that the problem is still not settled completely and that the above result is the best that is known.

I suppose it is still unsolved, but many partial results can be found among the references on Lohwater and Piranian on Mathscinet.

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Thank you very much for the interesting references, I will take a look at them. – Kalim Mar 12 '13 at 20:19

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