Take the 2-minute tour ×
MathOverflow is a question and answer site for professional mathematicians. It's 100% free, no registration required.

We know that every finite dimensional Lie group has no small subgroups. Is there any infinite dimensional Lie group which has small subgroups? Please explain your answer by refrence. Thanks so much.

share|improve this question
1  
Presumably, by the existence of "small subgroups", you mean that for every neighborhood of the identity $e\in G$, there should be a subgroup contained in that neighborhood. –  André Henriques Feb 12 '13 at 12:40
    
hossein, please see mathoverflow.net/howtask I think you are more likely to get help with your questions if you can demonstrate that you already know some details and have made some effort yourself –  Yemon Choi Feb 12 '13 at 17:47
add comment

1 Answer

The locally convex space $\mathbb R^{\mathbb N}$ (product of a countable number of copies of $\mathbb R$) equipped with the product topology can be made into an Abelian Lie group with respect to addition and the standard manifold structure. A local basis at the origin consists of open sets of the form $\Pi U_i$ where $U_i$ is an open neighborhood of $0$ in $\mathbb R$ and $U_i\neq\mathbb R$ for fintely many indices $i$ only. Such a neighborhood of $0$ contains nontrivial vector subspaces, so that $G$ contains small subgroups. This example is discussed in "Towards a Lie theory of locally convex groups", Karl-Hermann Neeb, Japan. J. Math. 1, 291–468 (2006).

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.