Take the 2-minute tour ×
MathOverflow is a question and answer site for professional mathematicians. It's 100% free, no registration required.

This question arises from an application to graphical models in probability theory, but I have abstracted that part out so only algebra remains. Let $\mathbb{R}$ denote standard field of real numbers and $\mathcal{R} = (\mathbb{R}\cup\{\infty\},\min,+)$ the tropical semiring. Let $\mathbb{Z}_n$ denote the cyclic group of order $n$.

Elements of the group ring $\mathbb{R}\mathbb{Z}_n$ are tuples $(x_0,\ldots,x_{n-1})$ and multiplication of these corresponds to discrete cyclic convolution. The Fast Fourier Transform gives an embedding $\mathbb{R}\mathbb{Z}_n\to\mathbb{C}^n$ (with elementwise sum and product). The FFT and its inverse can be computed in $O(n\log n)$ arithmetic operations, so elements of $\mathbb{R}\mathbb{Z}_n$ can be multiplied in $O(n\log n)$ arithmetic operations.

Define the group semiring $\mathcal{R}\mathbb{Z}_n$ in an analogous way. The product of $x = (x_0,\ldots, x_{n-1})$ and $y = (y_0,\ldots,y_{n-1})$ in this semiring is given by $(x\cdot y)_k = \min _{j \in \mathbb{Z}_n} (x_j + y_{k-j})$. This operation could perhaps be called "discrete cyclic infimal convolution" by analogy with the notion of infimal convolution in convex analysis. I'm not sure whether there is a more standard name -- this one does not pop up in quick google searches.

The naive way of computing a discrete infimal convolution uses $O(n^2)$ operations, just as the naive method for computing a standard cyclic convolution. My question is: is there a way to compute this "discrete cyclic infimal convolution" in $O(n\log n)$ arithmetic operations?

In convex analysis, there is an analog of the Fourier transform which turns infimal convolution into pointwise addition: the convex conjugate (or Fenchel or Legendre transformation). However, this operation only behaves nicely for convex functions, so it is not clear to me how one would translate it to an equivalent tool for $\mathcal{R}\mathbb{Z}_n$, but perhaps there is something there.

I would be interested in answers to the question regardless of whether they go through some analog of the Fourier transform. Also, I don't mind various restrictions such as making $n$ a power of $2$, replacing $\mathbb{R}$ with $\mathbb{Q}$, removing $\infty$ from the definition of the semiring, etc. Really anything on this theme would be helpful. Also any suggestions for better tags would be appreciated; perhaps this is a well-studied area I'm not aware of.

share|improve this question

2 Answers 2

Hi Noah,

Nice question! I tried thinking of the discrete fourier transform as a change of basis to the eigenbasis of a circulant matrix, but this did not generalize well tropically.

However, there are work on generalized Legendre-Fenchel transform to non convex/concave functions, including discrete ones, which preserves the convolution-to-sum property. See, for example

Characterization of a simple communication network using legendre transform

or

Slope transforms: theory and application to nonlinear signal processing

As to fast computation of the discrete Legendre-Fenchel transform, see Lucet's thesis:

La transformee de legendre-fenchel etla convexifiee d'une fonction: algorithmes rapides de calcul, analyse et regularite du second ordre

I haven't read the last two papers very carefully, but hopefully they're relevant. As a small observation, you can order either $y$ or $x$ in decreasing order, thus at least one of the Legendre transform is straight forward.

share|improve this answer
    
Thank you for these references. However, looking through them, they all seem to work with versions of the Legendre transform $^\ast$ which retain the standard property that $f^{\ast\ast}$ is the convex hull of $f$ (the function whose epigraph is the convex hull of the epigraph of $f$). As such, there doesn't seem to be a way to go back from $f^\ast + g^\ast$ to the infimal convolution of $f$ and $g$ when $f$ and $g$ are not convex. Am I missing something? –  Noah Stein Feb 13 '13 at 13:05
    
I just noticed that you are at Berkeley and working with Bernd Sturmfels, so I should mention that I had already emailed him about this yesterday before you replied. Please let me know if you two have any further thoughts about this. –  Noah Stein Feb 13 '13 at 16:06
    
Good point. They did mention the extended inverse Legendre transform in the first paper (and generally searching for "slope transform deconvolution" returns some papers with claims that it is possible to deconvolve for non-convex/concave functions, but I have yet to find something explicit). There are nice pictures in www2.ensc.sfu.ca/~ljilja/cnl/presentations/takashi/seminar.ps which explain the intuition of the extended Lengedre transform. Given that it keeps the information on all slopes, I would expect deconvolution to be possible. –  Ngoc Mai Tran Feb 13 '13 at 23:09
    
Ah yes, I learned of this problem from Bernd. –  Ngoc Mai Tran Feb 13 '13 at 23:52

After a bit more google searching, I found the 2006 paper Necklaces, Convolutions, and X+Y, which addresses this problem. The nine authors give an $O(n\sqrt{n})$ algorithm in the nonuniform linear decision tree model (I'm having little trouble pinning down the details of this computational model) and an $O\left(\frac{n^3(\log \log n)^3}{(\log n)^2}\right)$ algorithm in the real RAM model. I haven't found any newer results, so it seems that the problem I posed is open.

share|improve this answer
    
Regarding the etiquette of answering my own question in this way: do I accept this answer because it shows the problem is considered open, which is as far as MO is intended to go? Or not because I would still be happy for someone to answer it? –  Noah Stein Feb 18 '13 at 15:03

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.