2

This might be a little bit spesific but here it goes. While reading a paper (Brauer-Manin pairing...) by Yamazaki, I encountered this definition.

Let $V$ be a variety. $y$ be a one dimensional point on $V$, i.e. $dim\overline{ { y } } = 1$. Then let $C(y)$ be its closure in $V$ and $\tilde{C}(y)$ be normalization and $\bar C(y)$ be smooth completion. Let $C_\infty : = \bar C(y) - \tilde{C}(y)$. Then he definied the following group:

$UK^M_{r+1}:= ker [K_r^M(k(y)) \to \bigoplus_{x \in C_\infty}(K_{r-1}^M(k(x)) \oplus K_{r}^M(k(x))]$.

First component is the tame symbol at $x$. He defined the second component as $a \to \partial_x(a \cup \pi_x)$ where $\partial_x$ is the tame symbol at $x$ and $\pi_x$ is a uniformizer at $x$.

He says this group does not depend on the choice of the uniformizer, I couldn't see why it doesn't.

Is there an easy way to tell this group does not depend on the choice of the uniformizer?

flag

Your Answer

Get an OpenID
or

Browse other questions tagged or ask your own question.