if R=M_n(F) then Hom(M,M) = F

if R=M_n(F) then Hom(M,M) = F [closed]

let F be a field. let $R=M_n(F)$ and let M be unique irreducible R-module. Prove that $hom_R(M,M)$ is isomorphic to F (as a ring)

flag	asked Dec 17 at 19:51 unknown (google) 1

If you do your homework by yourself you'll learn a lot more. – Angelo Dec 17 at 19:55

its not homwork, its a problem in our book and we cannt solve that. we need to solution for final exam – unknown (google) Dec 17 at 20:17

read the faq, mathoverflow is not the right site to ask – Julian Kuelshammer Dec 17 at 21:50

Well, a buzzword is "Morita equivalence" or "Morita context". I agree with Angelo that you should work through the details yourself. – Todd Trimble Dec 17 at 22:07

closed as off topic by Angelo, Benjamin Steinberg, David White, Francesco Polizzi, Todd Trimble Dec 17 at 22:08

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