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How we should calculate the Lebesgue decomposition of a measure? Please explain it with an example such I can get the whole idea behind it.

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closed as off topic by Andres Caicedo, Michael Renardy, Anthony Quas, Alexandre Eremenko, Goldstern Dec 10 '12 at 23:58

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Have a look at the FAQ. This question does not belong here. –  Anthony Quas Dec 10 '12 at 23:49
This is a wrong place for this sort of questions. Please, read FAQ. –  Alexandre Eremenko Dec 10 '12 at 23:52

1 Answer 1

up vote 2 down vote accepted

Let e.g. $\nu$ be a finite Borel measure on $[a,b]$ and $m$ the Lebesgue measure. So the function $[a,b]\ni x\mapsto \nu\big([a,x)\big)$ is a BV function. It is therefore differentiable $m$-a.e., and its derivative $\rho(x)$ coincides with the Radon-Nikodym derivative of the absolutely continuous part of $\nu$. Knowing $\rho$ you can deduce the Lebesgue decomposition of $\nu$ wrto the Lebesgue measure: $\nu=\nu _ a+\nu _ s$ with $\nu _a\perp\nu _ s$ where $\nu_a(E)=\int_E\rho(x)dm(x)$.

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"Pietro Majer", thsnk you a lot. –  Omid Saba Dec 11 '12 at 4:34

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