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What is a schlicht domain over $\mathbb{C}^n$? How is it different from a domain in $\mathbb{C}^n$? Examples?

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up vote 3 down vote accepted

Schlicht domain over ${\mathbb C}^n$ is the same as a domain in ${\mathbb C}^n$. The point is that one also defines domains over ${\mathbb C}^n$ as connected complex manifolds $M^n$ equipped with a locally biholomorphic map $f:M^n\to {\mathbb C}^n$. The schlicht property just means that $f$ is 1-1.

See for general definition and references for Riemann domains. People also consider branched Riemann domains where "locally biholomorphic" is replaced with "holomorphic with discrete fibers." These are generalizations of Riemann surfaces of multivalued holomorphic functions of one variable.

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More on the "schlicht property":… – José Hdz. Stgo. Nov 22 '12 at 22:33
So, every domain in $\mathbb C^n$ is schlicht. – Saurabh T Nov 22 '12 at 22:50

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