MathOverflow is a question and answer site for professional mathematicians. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Maybe it is too easy but I want to know that: If $R$ is regular local ring of Krull dimension $2$ and $m$ is the maximal ideal of $R$. (It means that height $m$ is $2$). Can we find any ideal of height $2$ different from $m$?

share|cite|improve this question

closed as off-topic by Todd Trimble Jul 23 '14 at 13:03

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "MathOverflow is for mathematicians to ask each other questions about their research. See Math.StackExchange to ask general questions in mathematics." – Todd Trimble
If this question can be reworded to fit the rules in the help center, please edit the question.

    
Rolled back a pointless edit of an off-topic question – Yemon Choi Jul 26 '14 at 13:27

No. Since it is the unique maximal ideal, $\mathfrak m$ contains every prime ideal (its complement is the set of all units of $R$).

share|cite|improve this answer
    
thank you very much – maths Nov 12 '12 at 8:05

Not the answer you're looking for? Browse other questions tagged or ask your own question.