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why the integral closure of Z in Q(i) is Z(i)?

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 This is a standard computation from an intro algebraic number theory course, and as such not on topic here. It would probably get a good answer very quickly at math.stackexchange.com – David Speyer Oct 16 at 21:32
Read mathoverflow.net/faq – GH Oct 16 at 22:29

closed as off topic by David Speyer, Angelo, Gerry Myerson, Andreas Blass, GH Oct 16 at 22:29

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