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For closed n-manifolds M and N with the form $M\simeq M^{n-1}\cup _{f}e^n $,$N\simeq N^{n-1}\cup _{d}e^n$

Why $M\sharp N \simeq (M^{n-1}\vee N^{n-1})\cup _{f+d}e^n$?

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May I suggest consulting In particular, I wondering why is there a 6-cell in $N$ rather than one of some arbitrary dimension? –  David Roberts Oct 4 '12 at 10:47
reply to David Roberts:Sorry,it's a mistake which has been amended now. ^ ^! –  jinch Oct 4 '12 at 11:11
Isn't the answer within the definition of connected sum? –  Fernando Muro Oct 4 '12 at 11:15
reply to Fernando Muro:May I request an explanation in detail?Thank you! –  jinch Oct 4 '12 at 11:39
@jinch: that question may not be appropriate for a research level forum like this one. –  Fernando Muro Oct 4 '12 at 11:57

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