For closed n-manifolds M and N with the form $M\simeq M^{n-1}\cup _{f}e^n $,$N\simeq N^{n-1}\cup _{d}e^n$
Why $M\sharp N \simeq (M^{n-1}\vee N^{n-1})\cup _{f+d}e^n$?
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