Hi,

I know that in the diffeomorphism case the measure entropy of the T:M^{2}-->M^{2} (M smooth Rimannian surface) will be the same as the measure entropy of T^{-1}. But i need to know about the C^{2} endomorphism case. it seems that it can not be true, i want to know, what can be the relation between the entropy of T and its inverse? can we add some conditions which help us that the equality occurs again, maybe?

Thanks, Pooh