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I have the following question: let $U \subset \mathbb{C}^{n}$ be some open set containing zero. let $\tilde{U} = U \cap \mathbb{R}^{n}$. assume we have a real-valued analytic function $f : \tilde{U} \rightarrow \mathbb{R}$. Can this function be holomorphically extended to $U$ (maybe if we shrink $U$) in a unique way? I would be very thankful for answers.


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closed as off-topic by Ricardo Andrade, Stefan Kohl, David White, Willie Wong, Boris Bukh Dec 2 '13 at 23:08

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question does not appear to be about research level mathematics within the scope defined in the help center." – Ricardo Andrade, Stefan Kohl, David White, Boris Bukh
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up vote 6 down vote accepted

Yes, of course, after we shrink $U$. A convergent Taylor series at a real point converges in some complex neighborhood of this point.

Added reply to your comment: you can apply identity theorem. Two real analytic functions coinciding on an open set of $R^n$ coincide in a complex neighborhood of this set.

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but how can one apply the identity theorem in tis case (in oreder to get uniqueness)? – bruno Sep 23 '12 at 6:53

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