# If Fatou set has a Multiply connected Fatou component implies every component of F(f) is bounded

Recently when I read a paper about Fatou component, I met the following theorem which cited in Professor Eremenko's paper "on the iteration of entire functions"

If Fatou set has a Multiply connected Fatou component implies every component of F(f) is bounded.

it is really known theorem proved by I.N Baker in his paper in "The domains of normality of an entire function". However I really did know how to find this paper. any comments and materials about this theorem will be very appreciated. thanks.

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You do not specify which class of functions you are talking about: rational, polynomials, entire, meromorphic. –  Alexandre Eremenko Sep 9 '12 at 1:41

The correct statement is this. If the Fatou set $F(f)$ of an ENTIRE function has a multiply connected component, then all components of $F(f)$ are bounded. The idea of the proof is the following. Let $D$ be a multiply connected component. Then Maximum Principle implies that that the iterates tend to infinity in $D$, and if $\gamma$ is a non-trivial closed curve in $D$ then the index of the image of $\gamma$ under the iterates of $f$ tends to infinity. This implies that all other components (except $D$ itself) must be bounded. It remains to prove that $D$ is bounded. Here one uses Baker's theorem that an invariant component of $F(f)$ must be simply connected. This implies that $D$ must be wandering, that is some images of $\gamma$ "surround" $D$, so $D$ is bounded.