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I'm trying to figure out this assignment I'm doing. The task is to show that a conditional statement is a tautology without using truth tables.

This is the conditional statement: [-p && ( p || q )] -> q

Now Absorption law states that: p && ( p || q ) is equivalent to p

but how about when p is false, does it apply at all or am I dead wrong here?

could I get

-p -> q

this would work, but It would not prove that the statement is a tautology :$

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Please read FAQ before posting questions. – Kevin Walker Sep 6 at 15:35

closed as off topic by Kevin Walker, Todd Trimble, Emil Jeřábek, Tom Leinster, S. Sra Sep 6 at 17:13

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