I'm having some issue in understanding the channel capacity.
In particular the practical side. For example (an exercise), if I toss a fair coin and I transmit the result in a binary channel. What's the channel capacity?
I'm trying to imagine the channel graph. I believe is something like this.
H --1--> H
T --1--> T
A noiseless channel like this has $C=log|X|$ so $C=log2=1bit$. Why? I could represent it like this:
x --0.5--> H
x --0.5--> T
And the channel capacity becomes $C=log1=0$ because $|X|=1$.
Please someone help I'm quite confused.