A real function $f:X\rightarrow \mathbb{R}$ Is called **Baire-one function**, if there is a sequence $(f_n)_{n=1} ^\infty$ of continuous functions $f_n:X\rightarrow \mathbb{R}$ on $X$ so that for all $x\in X$ $$lim_{n\rightarrow \infty}f_n(x)=f(x)$$

When $X$ is a banach space, we have the following theorem refered to as **Baire factorization theorem**.

Theorem:The real function $f:X\rightarrow \mathbb{R}$ is in the class ofbaire-oneif and only if for all closed subset $K\subset X$, the restricted function $f|_K$ has a point of continuity with respect to $K$.

**Definition**: We denote the set of all baire-one real functions on the space $X$ by $Ba_1(X)$.

As you could easily see , $Ba_1(X)$ forms a ring with pointwise addition and multiplication. for simplicity Let me consider $X=[0 , 1]$.

suppose $C[0 , 1]$ denotes the ring of all continuous real valued functions on the interval $[0 , 1]$. by the theorem of **Gelfond and Kolmogroff** we Know that the set of all maximal ideals of the ring $C[0 , 1]$ is of the form {$M_x: x\in X$} ,Where $M_x=${$f\in C[0, 1]: f(x)=0$}.

Compared with the ring $C[0 , 1]$ we could easily find that the sets of the form $M_x^1=$

{$f\in Ba_1[0 , 1]: f(x)=0$} are maximal ideals of the ring $Ba_1[0 , 1]$. From this property some Questions came in my mind as follows:

Question1: Does there exist a maximal ideal in $Ba_1[0 , 1]$ other than maximal ideals of the form $(M_x^1$ for $x\in X)$

Question2: Is the ring $Ba_1[0 , 1]$ aring?$($i.e. a ring in which each prime ideal is contained in a unique maximal ideal.$)$PM-