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[Question previously asked on Math.SE]

Let $N$ be a von Neumann algebra, and $A$ be a dense $∗$-subalgebra of $N$ (in the ultraweak topology) with $A''=N$. Is it true that:

For any $x∈N^+$, there exists a increasing net $(x_j)$ in $A^+$ such that $x_j \to x$ in the ultraweak topology ?

The case of $A$ being an ideal of $N$ seems known (it is right?) but my question is about the general case.

(Precision: $A$ is not supposed to be normed closed.)

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2  
Have you considered the case when $N$ is abelian? E.g., $N = L^\infty[0,1]$, and $A = C[0,1]$. –  Jesse Peterson Jul 26 '12 at 23:53
    
If $A=C[0,1]$ as in Jesse's example above, for positive $t$ the functions $f_{t}(x)=min\{f(x),t\}$ will give us an increasing net converging to $f$. The trouble is that when $A$ is strictly smaller than $C[0,1]$ we can't know if such functions are to be found in $A$. Isn't this your problem, Michael? –  Jon Bannon Jul 27 '12 at 1:47
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Michael specifies explicitly that the subalgebra $A$ does not have to be norm-closed. In that case, an easy counter-example is the following: Consider the algebra of polynomials $A$ in $N=L^{\infty}([-1,1])$. Consider $f=1_{[0,1]}$ the characteristic function of half this interval. The constant function $0$ is the only positive function in $A$ that is also below $f$. Hence you can not approximate $f$ from below by positive polynomials. –  Steven Deprez Jul 27 '12 at 9:36
    
Steven's got it. Whatever you're trying to do, Michael, you're going to need some extra conditions on your dense *-subalgebra! –  Jon Bannon Jul 27 '12 at 10:15
    
@Jon: $f_t$ need not be continuous if $f$ isn't. –  Jesse Peterson Jul 27 '12 at 16:03
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