Sign up ×
MathOverflow is a question and answer site for professional mathematicians. It's 100% free, no registration required.

In Gromov's paper regarding this proof, he says that by taking the best possible $H$ , we can get the following result: Let $k>0 , x$ be such that $ 1-x \leq K \int_0^{\infty} J_{k,H} (t) dt $ and $ x \leq K \int_0^{\infty} J_{k,-H} (t) dt $ for some constant $K$ . He then says that this implies that $ K \geq \phi \circ \Phi^{-1}(x) $ , where:

$\phi(t) = \frac{sin^{n-1} ( \sqrt{k} t) }{\int_0^{\pi/\sqrt{k}}sin^{n-1} (\sqrt{k} s ) ds}$

$ \Phi(t)=\int_0 ^t \phi(s)ds $ , $J_{k,H} (t) = ( sLk ' (t) + \frac{H}{n-1} s_k(t) ) _+ ^{n-1} $ $ s_k(t) = \frac{sin(\sqrt{k} t ) }{\sqrt{k} } $ .

does someone have an idea about this conclusion? How did he deduce this fact?

thanks !

[[33].pdf ]

share|cite|improve this question
@Jeremy, do you think it might be possible to understand your question? (Better say what is the place in the paper your are trying to understand.) –  Anton Petrunin Jul 24 '12 at 12:26
Or at least provide more context for these constants, functions, and formulas. –  Deane Yang Jul 24 '12 at 12:38
I really cannot find these formulas in the paper you quoted. What is the precise page number? –  YangMills Jul 28 '12 at 16:00

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.