Given that $A$ is an invertible square matrix and $AA^T = A^TA = I$. Suppose that $B=A^{-1}A^T$ and $det A$ is not equal to $det B$. Show that $det (A+B) =0$.
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closed as too localized by Angelo, Federico Poloni, Gjergji Zaimi, Denis Serre, Vladimir Dotsenko Jul 16 at 10:04 |
