Let $X$ be a smooth projective variety, and let $E=\mathcal{O}\oplus \mathcal{O}(1)$ be a vector bundle of rank $2$. Then $L=\wedge ^{2} E $ is a line bundle on $X$. Is $L(2)$ $\mathbb{Q}$linear to an effective divisor?
The answer is no already for $X=\mathbb{P}^1$. Indeed $c_1(L)=c_1(\mathcal{O}(1))$ and so $c_1(L(2))=c_1(\mathcal{O}(1))$. Therefore $L(2)$ is linearly equivalent to the tautological bundle, which is not $\mathbb{Q}$effective. 

