MathOverflow will be down for maintenance for approximately 3 hours, starting Monday evening (06/24/2013) at approximately 9:00 PM Eastern time (UTC-4).
0

1

Hello everyone,

After reading RH ( Riemann's Hypothesis ) and Swinnerton-Dyer conjecture, I asked myself why can't RH hold for $L$-Functions ( Hasse-Weil L-function ). In particular the GRH imposes the location of finding zeroes of a $L$-function with $\chi$ character.

So in particular Swinnerton-Dyer's conjecture states that

The underlying Mordell-Weil group of an elliptic curve has an infinite cardinality if there is a zero at $s=1$. i.e. $$E(\mathbb{Q})=\infty \iff L(E,1)=0.$$ $$E(\mathbb{Q})<\infty \iff L(E,1)\neq 1.$$ So can we predict that Hasse-Weil L-function of an elliptic-cruve satisfies the GRH. After normalizing can we put it this way :

There are infinitely many zeroes in the critical strip of Hasse-Weil L-function $L(E,s). $ i.e. Let $\mathfrak{K} $ be the number of zeroes of the Hasse-Weil L-function. Then $\mathfrak{K}=\infty \iff s=1+it$ ? . ( Assume that $E$ has infinitely many points, other wise $L(E,s)\neq0$.

I have some more set of questions concerning the significance of zeroes . They can be stated as

  1. Are there any zeroes existing in the critical strip of $L(E,1+it)$ ? .
  2. We know that $\rm{Rank(E(\mathbb{Q}))}= \rm{ord}_{s=1} L(E,s).$ So what about the significance of order of vanishing for other zeroes which are located at $s=1+it$ . Do they have some interesting relation with the properties of elliptic curves ? .

Are there any interesting results that are published in this direction so far ?

Thank you.

flag
1 
More generally, there are generalizations of RH for any automorhic L-functions : see en.wikipedia.org/wiki/Grand_Riemann_hypothesis – François Brunault Jul 13 at 9:22
Thank you FYI. @FrançoisBrunault – Shanmukha_Srinivasan Jul 13 at 9:38
There are precise formulae to count the number of zeros on L(E,S) in the critical strip, up to a height T say. See: mathoverflow.net/questions/71061/… Moreover, it is generally believed that the nonreal zeros of L(E,s) are all simple. – Micah Milinovich Jul 14 at 16:52

1 Answer

3

In answer to question 1, there are certainly zeroes on the critical strip. A great way you can investigate this is to go to the L-Functions and Modular Forms Database, where you can view plots of the associated Hardy Z-functions associated to the Hasse-Weil L-function of any elliptic curve over $\Bbb Q$ with conductor less than 240000.

For example you can go to L-function of the elliptic curve 389a and see that the Z-function on the bottom appears to have a zero of multiplicity 2 at 0. (It actually does because this elliptic curve has rank 2!) You also see many zeros of the Z-function between 0 and 30, I count 34. So yes, there certainly a lot of zeros of this Hasse-Weil L-function on the critical line.

I don't know a lot about zeros of $L$-functions so I don't know if there order of vanishing at the zeros away from the central point means anything. I would guess that the probability that a randomly chosen zero is anything other than a simple zero is $0$. (Analogous to the conjecture that a randomly chosen elliptic curve has probably $0$ of having rank $> 1$. Experts in Random Matrix Theory would know better than me, and hopefully they will appear soon.

link|flag

Your Answer

Get an OpenID
or

Not the answer you're looking for? Browse other questions tagged or ask your own question.