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There are two formal semi-infinite Laurent series

$$ f_+(z)=z+\sum_{k=2}^{\infty} a_k z^k $$

and

$$ f_-(z)=z+\sum_{k=0}^{\infty} b_k z^{-k} $$

Their composition (we assume that this composition exists) $f_+(f_-(z))$ is a formal series infinite in both directions. Is there any way to construct two other semi-infinite series

$$ g_+(z)=z+\sum_{k=2}^{\infty} c_k z^k $$

and

$$ g_-(z)=z+\sum_{k=0}^{\infty} d_k z^{-k} $$

such that

$$f_+(f_-(z))=g_-(g_+(z))$$

How should I call this problem? Are there any non-trivial examples when it can be done?

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2  
It's not clear that the composition is well defined since each coefficient will be a sum of infinitely many terms. –  Felipe Voloch Jun 29 '12 at 17:13
    
That's true. Actually, in the "physical" example I have in my mind, coefficients are divergent. But if we assume that coefficients of the composition are well defined, what can be done? –  Sasha Jun 29 '12 at 17:23
1  
I'm sorry. But I am not even sure how to compute $g_-(g_+(z))$ where the $-$ part is on the outside. For example, if $g_-(z)$ has a term $z^{-1}$ and $g_+(z)=z+z^2$, we have $$\begin{align} \left(z+z^2\right)^{-1} &= z^{-1}-1+z-z^2++z^3-z^4+\dots\quad\text{for $z$ near $0$, but} \cr \left(z+z^2\right)^{-1} &= z^{-2}-z^{-3}+z^{-4}-z^{-5}+\dots\quad\text{for $z$ near $\infty$.} \end{align}$$ –  Gerald Edgar Jul 5 '12 at 14:54

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