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Let $X$ be $\Sigma^g$ which is the Riemann surface of genus $g$, and consider a trivial $G$-bundle over it.

1) In this $2$-d setting, the space of Yang-Mills central connections is the set of connections $A$ such that $*F(A)$ (the Hodge dual of its curvature) takes a constant value in the center of the Lie algebra $\mathfrak{g}$. If we let $G = U(n)$, and fix that central element in $\mathfrak{g}$ to be $-2\pi i \frac{k}{n}$ ($k$ is some integer) times the identity matrix, the "moduli space of bundles" is defined as the space of such Yang-Mills central connections $\mathcal{A}_{y-m}^{central, n, k}$ modulo the gauge group $\mathcal{G}$.

2) However, I find many people use a different setting which seems to be able to give the same moduli space. Here we let $Y = (\Sigma^g \backslash D^2, S^1)$, that is, $X$ with an open disc removed, leaving an $S^1$ as its boundary. Then we consider the space of flat connection $\mathcal{A}_0$ for the trivial $G$-bundle over $Y$ with the property that its holonomy around the $S^1$-boundary is $e^{-2\pi i \frac{k}{n}}$ times the identity matrix. After modding out gauge equivalence one will get the same moduli space. As a corollary one can readily see this is related to $U(n)$ representations of a certain central extension of $\pi_1(\Sigma^g)$.

My question is, what is the best (and rigorous) method to see the two methods are describing the same object? Thank you.

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    $\begingroup$ Can you give some good reference from which one can study these topics? $\endgroup$
    – Anirbit
    Jun 22, 2010 at 18:32
  • $\begingroup$ Hi Anirbit, the best starting point may be Atiyah and Bott's classic paper "Yang-Mills equations over Riemann surfaces". $\endgroup$
    – Bo Peng
    Jun 23, 2010 at 5:53
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    $\begingroup$ You should take a look at Segal's book on loop groups. There is a chapter explaining this. $\endgroup$
    – Orbicular
    Jun 26, 2010 at 17:48
  • $\begingroup$ Removed yang-mills tag. There is no need for it as any question about Yang-Mills equations should contain it as a keyword and searchable as such. (Also this was the only question with a yang-mills tag anyway.) $\endgroup$ Jul 10, 2010 at 14:53

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