7
$\begingroup$

Let $S$ be a orientable compact surface with a flat euclidean structure with conical singularities (cf. [T] for instance). Let also $\mathcal P$ be a polyhedral euclidean decomposition of $S$ (with vertices at the singular points of the euclidean structure of $S$).

Question 1: can $S$ be realized (as a polyhedral surface) in an euclidean space? If yes, what is known about the set of such `euclidean polyhedral realizations'?

Question 2: same questions than above, but for $\mathcal P$ (i.e. an euclidean polyhedral decomposition of $S$ is fixed).

--

Remarks:

  • there is no assumption on the genus of $S$ (when $S$ has genus 0, an answer to the (first part of) Question 1 is given by Alexandrov theorem)

  • A similar question (but for Riemann surfaces) already appears in [B] (page 9). I guess that a lot has been done on this problem since. Any relevant reference would constitute an interesting answer.

Thanks for any help!


[B] Bers L., Riemann surfaces (1958)

[T] Troyanov M. -- Les surfaces a singularités coniques. Enseign. Math. 32 (1986), 79–94.

$\endgroup$
1
  • $\begingroup$ For genus 0, this is discussed in the monograph of Jürgen Richter-Gebert "Realization spaces of polytopes." It is published by Springer. There are still PDF copies archived on citeseer and other sites that you can find with google. $\endgroup$
    – j.c.
    Sep 24, 2013 at 14:05

1 Answer 1

9
$\begingroup$

It may be that this theorem of Burago & Zalgaller (partially) answers your question?

Theorem (Burago-Zalgaller 1.7). Every polyhedron $M$ admits an isometric piecewise-linear $C^0$ immersion into $\mathbb{R}^3$. If $M$ is orientable or has a nonempty boundary, then $M$ admits an isometric piecewise-linear $C^0$ embedding into $\mathbb{R}^3$.

This is from:

  • Yu. D. Burago and V. A. Zalgaller. "Isometric piecewise linear immersions of two-dimensional manifolds with polyhedral metrics into $\mathbb{R}^3$. St. Petersburg Math. J., 7(3):369--385, 1996. Translated by S. G. Ivanov. English translation: Scanned PDF (15MB).

Here is their definition of a "polyhedron":

By a two-dimensional manifold with polyhedral metric (in brief, a polyhedron), we mean a metric space endowed with the structure of a connected compact two-dimensional manifold (possibly with boundary) every point $x$ of which has a neighborhood isometric to the vertex of a cone. ... The metric is locally flat everywhere except for a finite collection of points; these points are the `true' vertices."

A nice phrase they use in Lemma 2.2 to describe the mapping is that each triangle becomes a pleated surface in $\mathbb{R}^3$.

$\endgroup$
5
  • $\begingroup$ Thanks a lot! Burango-Zalgallar theorem is quite impressive and is certainly the best answer that can be expected to the first part of Question 1. $\endgroup$
    – Lucien
    Sep 16, 2013 at 13:55
  • $\begingroup$ It is an amazing theorem! I believe they do not attempt to bound the number of flat, noncreased triangles in the final construction, but it would be astronomical in most cases. $\endgroup$ Sep 16, 2013 at 14:18
  • $\begingroup$ Dear Joseph - Do you have a copy of the English translation? I've not been able to find it online? Thank you! $\endgroup$
    – Sam Nead
    Apr 19, 2020 at 14:40
  • $\begingroup$ @SamNead: Added a link to a scanned PDF. $\endgroup$ Apr 19, 2020 at 14:45
  • $\begingroup$ Brilliant - thank you! $\endgroup$
    – Sam Nead
    Apr 19, 2020 at 20:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.