User hany - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-25T12:57:03Zhttp://mathoverflow.net/feeds/user/7886http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/45185/pseudonyms-of-famous-mathematicians/45325#45325Answer by Hany for Pseudonyms of famous mathematiciansHany2010-11-08T17:07:44Z2010-11-08T17:07:44Z<p><a href="http://arxiv.org/find/all/1/all%3A+polymath/0/1/0/all/0/1" rel="nofollow">D. H. J. Polymath</a> is a pseudonym for a collective of mathematicians (some of them may be not professional mathematicians).</p>
http://mathoverflow.net/questions/43848/two-sequences-whose-difference-converges-to-zero/43858#43858Answer by Hany for two sequences whose difference converges to zeroHany2010-10-27T19:22:05Z2010-10-27T19:22:05Z<p>For sequences of real numbers there is a French term: "suites adjacentes" (may be translated as adjacent sequences) which means that the two sequences satisfy $\lim_{k\to\infty}(A_k-B_k)=0$, but with $A_k$ decreasing and $B_k$ increasing.</p>
http://mathoverflow.net/questions/43792/riemann-stieltjes-derivative/43843#43843Answer by Hany for "Riemann-Stieltjes derivative" ?Hany2010-10-27T18:00:13Z2010-10-27T18:00:13Z<p>Let $G:[0,1]\longrightarrow[0,1]$ be a continuous increasing function that is constant on each subinterval of the complement of the Cantor ternary set $K$ and satisfying $G(0)=0, G(1)=1$.</p>
<p>The Riemann-Stieltjes integral with respect to $G$ cannot be 'differentiated'. Consider a function $F(x)$ and suppose there is some Riemann-Stieltjes integrable function $h$ such that
$$ F(b)-F(a)=\int_a^b h(t)dG(t),\quad \forall a,b \in[0,1]$$
Then, as the R.H.S. vanishes on any interval contained in the complement of $K$, $F$ must be constant on each such interval. So $F(x)=x$ for example cannot satisfy the above formula.</p>
http://mathoverflow.net/questions/43381/what-numbers-can-be-approximated-pretty-well-by-rationals/43560#43560Answer by Hany for What numbers can be approximated "pretty well" by rationals?Hany2010-10-25T18:53:36Z2010-10-26T19:35:50Z<p><a href="http://books.google.com.eg/books?id=rey9wfSaJ9EC&printsec=frontcover&dq=Hardyand+wright+number&source=bl&ots=avj7HPEGSa&sig=ZBqVYG6xeXOSbwcC5mUxM-ql_uQ&hl=ar&ei=pdHFTLeQOca54gb28OC6Aw&sa=X&oi=book_result&ct=result&resnum=10&ved=0CEgQ6AEwCQ#v=onepage&q&f=false" rel="nofollow">Hardy and Wright</a> devoted a chapter (chapter 9) to these questions. One interesting theorem related to your question is theorem 196.</p>
http://mathoverflow.net/questions/12085/experimental-mathematics/42197#42197Answer by Hany for Experimental MathematicsHany2010-10-14T19:11:37Z2010-10-14T19:11:37Z<p>Didn't the work of Candès and Tao on compressed sensing begin by a computer experiment by Candès that gave results "too good to be true"?
See: <a href="http://www.ams.org/samplings/math-history/hap7-pixel.pdf" rel="nofollow">http://www.ams.org/samplings/math-history/hap7-pixel.pdf</a></p>
http://mathoverflow.net/questions/41245/proof-that-bases-etc-exist-in-early-linear-algebra-course/41271#41271Answer by Hany for Proof that bases etc. exist in early linear algebra course?Hany2010-10-06T13:32:49Z2010-10-06T13:32:49Z<p>I do not really know what is the level of the course and what else is in the syllabus, but there are many excellent books in linear algebra that cover abstract vector spaces almost painlessly.
A good book to find this stuff is Axler's "Linear Algebra Done Right".</p>
http://mathoverflow.net/questions/40528/spencer-browns-claimed-proof-of-the-four-color-theoremSpencer-Brown's claimed proof of the four color theoremHany2010-09-29T19:59:59Z2010-09-30T09:38:36Z
<p>I read on <a href="http://en.wikipedia.org/wiki/G._Spencer-Brown" rel="nofollow">Wikipedia</a> that G. Spencer-Brown gave a non-computer based proof of the four color theorem. As I'm not an expert in the subject I'm unable to verify that claim. Does any one have an idea about the proof or a reference to a serious discussion of the subject?</p>
http://mathoverflow.net/questions/34251/the-dual-group-of-mathbb-qThe dual group of $\mathbb Q$Hany2010-08-02T12:13:34Z2010-08-20T09:49:13Z
<p>What is the dual group of the additive group of rational numbers equipped with the standard topology inherited from $\mathbb R$? As a group, this dual group is isomorphic to $\mathbb R$ (see the answer of Ekedahl given below), but it should be equipped with the topology of uniform convergence on compact subsets of $\mathbb Q$. What are the properties of this group? Is it locally compact? what are its connected components? does it have more natural structure? </p>
http://mathoverflow.net/questions/45185/pseudonyms-of-famous-mathematicians/45206#45206Comment by HanyHany2010-11-08T19:56:32Z2010-11-08T19:56:32ZIf you mean by Al-Khoresmi "Abu Ja'far Muhammad ibn Musa Al-Khwarizmi"
then I think he does not qualify. It was customary at the time to use geographic names of family origin as family name. This means that he had the name "Al-Khwarizmi" all his life and that his father, brothers and sons (if he had any) had the same name. http://mathoverflow.net/questions/44705/cardinalities-larger-than-the-continuum-in-areas-besides-set-theory/44709#44709Comment by HanyHany2010-11-03T21:43:00Z2010-11-03T21:43:00ZFor the example of measurability I would say it is still within the realm of set theory (descriptive set theory).
I think there are results on infinite dimensional topology that require a space of very large cardinality, but the ideas and techniques are borrowed from model theory.
Actually it seems that whenever we study questions of infinite cardinals we require tools from model theory or set theory.
http://mathoverflow.net/questions/44265/question-about-schauder-bases-in-c0-1/44280#44280Comment by HanyHany2010-10-30T22:29:33Z2010-10-30T22:29:33ZThe usual example in $C([0,1])$ is $\vert t-\frac 12\vert$. Its Fourier series does not converge uniformly.http://mathoverflow.net/questions/44265/question-about-schauder-bases-in-c0-1Comment by HanyHany2010-10-30T20:27:30Z2010-10-30T20:27:30ZActually if a trigonometric series converges uniformly to a function $f$, then the series must be the Fourier series of $f$. This is statement 1.41 on page 6 of Zygmund's {\it Trigonometric Series}.
http://mathoverflow.net/questions/43864/describe-subsets-of-the-integers-closed-under-the-binary-operation-axby/43905#43905Comment by HanyHany2010-10-28T07:09:15Z2010-10-28T07:09:15ZWouldn't $(1)$ be the set of all integers of the form $F(A+B)$ where $F$ is a polynomial with positive integer coefficients?http://mathoverflow.net/questions/43848/two-sequences-whose-difference-converges-to-zero/43858#43858Comment by HanyHany2010-10-27T21:56:04Z2010-10-27T21:56:04ZYes. I thought it may suggest a suitable terminology.http://mathoverflow.net/questions/43792/riemann-stieltjes-derivative/43794#43794Comment by HanyHany2010-10-27T16:48:50Z2010-10-27T16:48:50ZThe existence of the Radon-Nikodym derivative requires that the measure $dF$ be absolutely continuous with respect to Lebesgue measure which is not satisfied by a pure jump function where the support of the measure is a finite or countable set.http://mathoverflow.net/questions/43538/wonderful-applications-of-the-vandermonde-determinant/43548#43548Comment by HanyHany2010-10-26T19:20:51Z2010-10-26T19:20:51ZAnother application is to prove that for any $0<\alpha_1<\cdots<\alpha_n$ the family
$$ \sin \alpha_1x,\cdots,\sin\alpha_nx$$
is linearly independent in $C^{4(n-1)}(\mathbb R)$.http://mathoverflow.net/questions/42215/does-constructing-non-measurable-sets-require-the-axiom-of-choiceComment by HanyHany2010-10-15T08:46:26Z2010-10-15T08:46:26ZThere is an interesting discussion on: <a href="http://www.math.niu.edu/~rusin/known-math/99/AD_AC" rel="nofollow">math.niu.edu/~rusin/known-math/99/AD_AC</a>http://mathoverflow.net/questions/41493/explicit-isomorphism-between-distributions-and-universal-enveloping-algebra/41496#41496Comment by HanyHany2010-10-08T11:25:15Z2010-10-08T11:25:15Z@Najdorf- It seems that $D.\delta_e$ should act as $D$ according to
$$ <(D.\delta_e)\varphi,\psi>=<\delta_e\varphi,D\psi>$$http://mathoverflow.net/questions/34251/the-dual-group-of-mathbb-q/34254#34254Comment by HanyHany2010-08-10T14:45:05Z2010-08-10T14:45:05Z@Edgar: Thanks for the correction. http://mathoverflow.net/questions/34251/the-dual-group-of-mathbb-q/34254#34254Comment by HanyHany2010-08-06T09:02:18Z2010-08-06T09:02:18Z@Victor: Consider $X={\mathbb R}\cup\{\infty\}$ with the topology consisting of the discrete topology on $\mathbb R$ and with a base of neighborhoods at $\infty$ consisting of intervals $]k,\infty]$ with $k\in{\mathbb N}$. Compact sets in this space are finite, but the space is not discrete.