User - MathOverflowmost recent 30 from http://mathoverflow.net2013-06-19T10:31:17Zhttp://mathoverflow.net/feeds/user/5318http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/21147/divide-and-conquer-method-to-compute-rootsDivide and conquer method to compute rootshellsoul1532010-04-12T19:27:57Z2010-04-12T22:56:15Z
<p>Hello,</p>
<p>Knowing that we can use Divide-and-Conquer algorithm to compute large exponents, for exemple 2 exp 100 = 2 exp(50) * 2 exp(50), which is quite more efficient, is this method efficient using roots ? For exemple 2 exp (1/100) = (2 exp(1/50)) exp(1/50) ?</p>
<p>In other words, I'm wondering if (n exp(1/x)) is more efficient to (n exp(1/y)) for x < y and where x and y are integers.</p>
<p>There seems to be a method using Dichotomic search and Divide-and-conquer method to know if n exp(1/i) is an Integer. See Dixon's factorisation method : <a href="http://en.wikipedia.org/wiki/Dixon" rel="nofollow">http://en.wikipedia.org/wiki/Dixon</a>'s_factorization_method</p>