User ivan - MathOverflowmost recent 30 from http://mathoverflow.net2013-06-19T20:25:40Zhttp://mathoverflow.net/feeds/user/4235http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/13733/wild-ramification/129419#129419Answer by Ivan for Wild RamificationIvan2013-05-02T12:54:55Z2013-05-02T12:54:55Z<p>There is the following work of Kerz and Saito:</p>
<p><a href="http://arxiv.org/abs/1304.4400" rel="nofollow">http://arxiv.org/abs/1304.4400</a></p>
<p>In particular, one can view their Coro. II as a higher-dimensional analogue of the existence theorem, which encodes p-extensions (see Artin-Schreier-Witt theory), and hence wild ramification for varieties.</p>
http://mathoverflow.net/questions/122298/voevodskys-proof-in-any-characteristic-for-motivic-and-chowVoevodsky's proof in any characteristic (for motivic and Chow)Ivan2013-02-19T13:27:01Z2013-02-19T22:35:03Z
<p>Regarding the published version of "Motivic cohomology groups are isomorphic to higher Chow groups in any characterstic" (IMRN) available at:</p>
<p><a href="http://imrn.oxfordjournals.org/content/2002/7/351.full.pdf" rel="nofollow">http://imrn.oxfordjournals.org/content/2002/7/351.full.pdf</a></p>
<p>I would appreciate any elucidation on the following two points:</p>
<p><strong>(1)</strong> a short assertion is made on the second page whose proof is not entirely clear to me </p>
<p>and</p>
<p><strong>(2)</strong> how this assertion factors into the proof of Theorem 1.</p>
<p><strong>For (1)</strong> the short assertion is (from page 2, second paragraph from top):</p>
<p>For any smooth scheme $X$ (of finite type) over a field $k$, $x$ a point of $X$ and $k_0$ the subfield of constants of $k$, there exists a smooth variety $X_0$ over $k_0$ and a point $x_0$ on $X_0$ such that the local rings $O_{X, x}$ and $O_{X_0, x_0}$ are isomorphic. </p>
<p>As noted, the dimension of $X_0$ may be larger than that of $X$. Here is an example I worked out that I think illustrates the principle of the proof:</p>
<p><strong>Example</strong>. Let $k = \mathbb{F}_p(t), X = \mathbb{A}^1_k$ with parameter $T$, and let $x$ correspond to $(T-0)$. Then $k_0 = \mathbb{F}_p$ and put $X_0 = \mathbb{A}^2_{k_0}$ with parameters $u, v$. Then via $u\mapsto T, v\mapsto t$, and $x_0$ corresponding to $(u-0)$, we have the desired isomorphism of local rings. Note that the residue fields of the local rings are $\mathbb{F}_p(t)$ and $\mathbb{F}_p(v)$, respectively.</p>
<p><strong>In general</strong> (<em>assuming $k$ is absolutely finitely generated, i.e. is finitely generated over its prime field</em>): since the question is local, we assume $X$ affine: $X = Spec(A)$ with $A = k[T_1, \ldots, T_n]/I$. Then take a transcendence basis $t_1, \ldots, t_r$ of $k$ over $k_0$. Then it seems that $X_0$ is built from $T_1, \ldots, T_n, t_1, \ldots, t_r$, but I haven't worked this out in general.</p>
<p><strong>Problem</strong>: what if $k$ does not have finite transcendence degree over $k_0$? In the absolutely finitely generated case, if $F$ is the prime field of $k$, then $k_0$ is a finite extension of $F$ and $tr.deg_F(k) = tr.deg_{k_0}(k)$. </p>
<p><strong>As for (2)</strong>, the part that is not clear to me is when one passes from $X$ to $X_0$ in the course of the proof of the above cited paper (for example, in Prop 4).</p>
<p>NB: the above cited assertion is <em>not</em> included in the preprint <a href="http://www.math.uiuc.edu/K-theory/378/allagree.pdf" rel="nofollow">http://www.math.uiuc.edu/K-theory/378/allagree.pdf</a></p>
<p>Cf. the sentence directly after Corollary 2 on page 1 of this preprint</p>
http://mathoverflow.net/questions/69120/normal-crossing-divisor-v-s-strict-normal-crossing-divisor/101445#101445Answer by Ivan for normal crossing divisor v.s. strict normal crossing divisorIvan2012-07-05T23:38:33Z2013-01-21T18:19:56Z<p>Here is the definition of an sncd (and ncd) from SGA (SGA 5, 3.1.5, pg 24):</p>
<p>Let $X$ be a regular scheme and $D$ an effective divisor on $X$. </p>
<p>DEF: $D$ is an sncd on $X$ if there is a finite family of sections $(f_i)_{i\in I}$, $f_i\in O_X(X)$ such that the following two conditions hold:</p>
<p>i) $D = \sum_{i\in I}$ $div(f_i)$</p>
<p>ii) for each $x\in Supp(D)$, the local restrictions $(f_i)_x$ that satisfy $(f_i)_x \in m_x$ (i.e. those that land in the maximal ideal of $O_{X,x}$) have the property that they form a part of a regular system of parameters for the local ring $O_{X,x}$.</p>
<p>DEF: an effective divisor $D$ is an ncd if (i) and (ii) hold 'etale locally.</p>
<p>This definition is unambiguous (unlike Hartshorne, Wikipedia, etc) since, e.g., regularity is not a relative condition (whereas smoothness is a relative condition). Further, you can check that two smooth hyperplanes meeting transversally in an affine neighborhood, e.g. the x-y axis in $A^3_k$ for $k$ a field, form an sncd.</p>
<p><strong>Example / Remark</strong> : in SGA 5 they write <em>global</em> sections for an sncd. So here is an example of an ncd that is not an sncd: let $X = \mathbb{P}^1_k$ be the projective line over a field $k$ and consider an affine open $U = \mathbb{A}^1_k = Spec \; k[t]$. Now, the divisor defined by $t$ is not an sncd on $X$ as $t\not\in O_X(X) = k$ but since $U\hookrightarrow X$ is etale, then this divisor is an ncd on $X$. </p>
<p>Perhaps it's a matter of taste whether one defines sncd globally as in SGA 5 or Zariski locally...</p>
<p>(N.B. in EGA IV you can find the definitions of div and Supp)</p>
http://mathoverflow.net/questions/17634/definition-of-chow-groups-over-spec-zDefinition of Chow groups over Spec ZIvan2010-03-09T18:13:02Z2012-03-24T02:18:56Z
<p>Usually (eg, intro. in M. Rost's 'Cycle modules with coefficients'), for a variety, $X$, over a field one can define the Chow group of p-cycles, $CH_p (X)$, as
$$CH_p (X) = coker\; \left[\bigoplus_{x\in X_{p+1}} k(x)^\times \rightarrow \bigoplus_{x\in X_p} \mathbb{Z}\; \right]$$.</p>
<p>What about for an arithmetic scheme, eg when $X$ is, say, normal, separated, of finite type and flat over $Spec \; \mathbb{Z} $? Does something go wrong with the above definition?</p>
<p>Peter Arndt had posed part of this question already, but it seems without an answer.</p>
http://mathoverflow.net/questions/26558/on-semi-local-schemesOn semi-local schemesIvan2010-05-31T11:03:08Z2010-05-31T13:49:48Z
<p><strong>Background</strong>
I have searched a bit for the definition/constructions on how to "semi-localize" a scheme, but have been unsuccessful in finding a good reference; I apologize in advance if this topic has been covered in detail elsewhere (e.g. in a book or article) and would be happy for a reference!</p>
<p>This question arose from a problem I had been working on in finding an étale morphism into affine space. </p>
<p>Much of the terminology here will be from EGA I. </p>
<p>(Aside: The constructions below take place in the Zariski site but I think some of them go through in the étale/Nisnevich site)</p>
<p><strong>Definitions</strong>
A <em>local scheme</em> is the spectrum of a local ring and a <em>semi-local scheme</em> the spectrum of a semilocal ring. In the constructions below a ring $O_{X,C}$ is given, so then the candidate semi-local scheme is $Spec \; O_{X,C}$.</p>
<p>NB: for some reason I was having trouble with "\varinjlim" here, so I'm using "lim" below to mean direct limit i.e. colimit.</p>
<p><strong>Question</strong></p>
<p>Given a scheme $X$ we can <em>localize</em> $X$ at a point $x\in X$ by taking $$O_{X,x} := \lim_{U\ni x} O_X(U). $$</p>
<p>Suppose now that we are given a finite set of closed points $x_1,\ldots, x_n \in X$.
Let $C :=$ {$x_1,\ldots, x_n $}. How can we 'localize' $X$ around $C$?</p>
<p>There are at least three ways I know how to do this procedure and would be happy to hear about other methods as well as comments (especially geometric ones) regarding the following constructions:</p>
<p>$1.$ Define $$O_{X,C} : = \lim_{U\supset C} O_X(U).$$</p>
<p>This construction is similar to the localization construction above in that we take opens $U$ of $X$ containing $C$ and then take the direct limit; the case $n=1, C = {x_1}$ is then a special case. NB: we can 'see' this direct limit in the sense that for each $x_i$ we find an open $U_i\ni x_i$, then taking the (finite!) union of the $U_i$ we obtain an open $U$ containing $C$. Just as in the local case above, this direct limit is filtered by inclusion.</p>
<p>$2.$ Further assume now that $X$ is locally noetherian and regular. Let $A_i: = O_{X,x_i}$ and then define $$O_{X,C}:= \prod_i A_i .$$</p>
<p>Using the hypothesis that $X$ is regular, we can argue that the maximal ideals here correpsond to the $x_i$: the maximal ideals in $\prod_i A_i$ are generated by elements of the form $(1,1,\ldots, b_{ij},1,\ldots, 1)$ where the $b_{ij}$ generate $x_i$ (here is where we are using the two added hypothesis), i.e. that $(b_{ij})_{1\leq j\leq n_i} = m_i$ where $m_i$ is the max ideal corresponding to $x_i$ and $n_i = dim O_{X,x_i}$.</p>
<p>This construction is more ad-hoc (I think) vs. 1. Moreover, the geometry here is slightly more explicit in that this $Spec \; O_{X,C}$ is a finite disjoint union of local schemes, whereas in case 1, the topology is less disjoint when looking at neighborhoods of the $x_i$.</p>
<p>$3.$ With $X$ any scheme (no additional hypothesis as in 2), let $F_i : = O_{X,x_i}/m_i$ where $m_i$ is the maximal ideal corresponding to the closed point $x_i$. Define: $$O_{X,C}: = \prod_i F_i .$$ This construction is the most disjoint of the three in that the spectrum is now we have a finite coproduct of ''points''.</p>
<p><strong>Closing remarks</strong>
Presently, for me the most useful of the three is 1 and I would appreciate feedback on where the process of semi-localization has been defined. A professor that I admire very much once said (during a lecture) "from now on and for the rest of your life, every time you see something in commutative algebra, try to relate it to geometry, and vice versa" (I'm paraphrasing).</p>
http://mathoverflow.net/questions/26266/spectral-sequences-in-number-theory/26282#26282Answer by Ivan for spectral sequences in number theoryIvan2010-05-28T16:30:40Z2010-05-29T13:59:07Z<p>I posit the following example, in response to your ambiguous question:</p>
<p>The coniveau spectral sequence seems to play an important role in 'arithmetic geometry'. One instance is in class field theory for schemes:</p>
<p>From W. Raskind's nice survery article "Abelian class field theory of arithmetic schemes" [AMS, 1992, pgs. 100-101]:</p>
<p>Let $X$ be an arithmetic scheme, $n>0$ invertible on $X$. Then there is a coniveau spectral sequence (in the etale site):</p>
<p>$$E^{p,q}_1 = \bigoplus _{ x\in X^{p} } H^{q-p} (k(x), \;\mathbb{Z}/n \; (j-p)) \Rightarrow H^{p+q} (X, \mathbb{Z}/n \;(j)) $$</p>
<p>Without going into more details, this sequence plays an important role in defining a reciprocity map from a class group of $X$ to abelian fundamental groups.</p>
<p>That's all I will say for now in hopes that the above provides for motivation to delve further into studying coniveau, etc.</p>
<p>Finally, one of the best articles I have seen on coniveau is by Colliot-Thélène, Hoobler, and Kahn, "The Bloch-Ogus-Gabber theorem" which can be found at:
<a href="http://www.math.jussieu.fr/~kahn/preprints/prep.html" rel="nofollow">http://www.math.jussieu.fr/~kahn/preprints/prep.html</a></p>
<p>It might be nice to have others' remarks/comments on coniveau, but I don't have any precise questions yet.</p>
http://mathoverflow.net/questions/22883/etale-coverings-of-certain-open-subschemes-in-spec-o-k/23199#23199Answer by Ivan for Etale coverings of certain open subschemes in Spec O_KIvan2010-05-01T20:45:39Z2010-05-01T20:45:39Z<p>@Ariyan and BCnrd: Cf. Exercise 1.9, Section 4.1 of Q. Liu's wonderfully written book, "Algebraic Geometry and Arithmetic Curves".
@Ariyan: Exercise: re-write the one-dimensional (i.e. classical) idele class group as a certain complement of $Spec\mathcal{O}_K$...cf. the intro to "Global class field theory" by Kato-Saito.</p>
http://mathoverflow.net/questions/16331/when-does-a-projective-morphism-give-an-etale-morphism-into-affine-space-finiWhen does a projective morphism give an etale morphism (into affine space)? (Finite field) (normalization)Ivan2010-02-25T00:07:39Z2010-02-26T00:29:37Z
<p>Does anyone know of generalizations on what Mumford (Red Book) calls "uniformizing parameters"? For example, given a regular quasi-projective scheme over a <em>finite</em> field $\mathbb{F}$, is there an etale morphism into affine space over $\mathbb{F}$?. </p>
http://mathoverflow.net/questions/15781/given-a-number-field-k-when-is-its-hilbert-class-field-an-abelian-extension-of/16340#16340Answer by Ivan for Given a number field $K$, when is its Hilbert class field an abelian extension of $\mathbb{Q}$?Ivan2010-02-25T01:12:56Z2010-02-25T01:12:56Z<p>Is there a good/intuitive way to generate a stock of examples of <em>non-abelian</em> unramified extensions? The only examples I know of are a bit unintuitive (eg in Janusz's book). Intuition might suggest to start looking at Galois extensions with group equal to semi-direct products. I was originally interested in this question by the necessity of "ab" on the rhs of <code>$H^{1} (X_{Zar}\,, \mathcal{O}_{X} ^ {*}) = \pi_{1} ^{ab} (X), \; \; X = Spec\; \mathcal{O}_K$</code> (re-interpretation of unramified global cft).</p>
http://mathoverflow.net/questions/105381/henselization-and-completionComment by IvanIvan2013-02-25T15:28:36Z2013-02-25T15:28:36Zside remark: (from Liu's Alg. geom. book, 8.2.40 (b)) a regular local ring $R$ is excellent if $Frac(\hat{R})$ is separable over $Frac(R)$ (i.e. if every finitely-generated subextension is separable). Hence, a way to check if a dvr is excellent. As an example, consider the henselization of $k[x,y]$ at the prime (y), for $k$ a field of char $p>0$. This henselization is sometimes denoted by $k(x)\{y\}.$http://mathoverflow.net/questions/122298/voevodskys-proof-in-any-characteristic-for-motivic-and-chow/122357#122357Comment by IvanIvan2013-02-20T12:54:20Z2013-02-20T12:54:20ZThank you for the clear explanation!http://mathoverflow.net/questions/122298/voevodskys-proof-in-any-characteristic-for-motivic-and-chowComment by IvanIvan2013-02-19T19:34:06Z2013-02-19T19:34:06ZMarc: Thanks for your comment. What do you intend to show by saying a field is not of the form of a local ring in your first sentence? Perhaps you meant something about the residue fields? In general, residue fields of local rings can have infinite transcendence degree over the prime field. – Ivan 2 mins ago
http://mathoverflow.net/questions/28496/what-should-be-learned-in-a-first-serious-schemes-course/28617#28617Comment by IvanIvan2010-06-25T14:26:39Z2010-06-25T14:26:39ZSpeaking of Mumford and arithmetic approaches, it seems the fabled "Mumford-Lang" type-script has been subsumed by notes of Mumford/Oda (Lang is not mentioned as a coauthor here). In these notes they discuss Galois theory for schemes. Cf. especially Chapter 4 (Part I) of
<a href="http://www.math.upenn.edu/~chai/624_08/math624_08.html" rel="nofollow">math.upenn.edu/~chai/624_08/math624_08.html</a>
For a student with a background in algebraic number theory, Grothendieck's version of Galois theory may provide for added motivation to learn about schemes
http://mathoverflow.net/questions/26558/on-semi-local-schemesComment by IvanIvan2010-05-31T13:23:58Z2010-05-31T13:23:58Z@Qing Liu, I think you are correct on (1) especially bc in my application I was lucky enough that I could perform a change of coordinates to ensure that $C$ is contained in an open affine. I don't have any counterexamples yet, but appreciate the comment.http://mathoverflow.net/questions/26266/spectral-sequences-in-number-theoryComment by IvanIvan2010-05-30T16:51:25Z2010-05-30T16:51:25ZI'm neutral as to whether or not this question is taken down. If people find the comments/answers here useful, then perhaps leaving it up is ok.
http://mathoverflow.net/questions/26266/spectral-sequences-in-number-theory/26282#26282Comment by IvanIvan2010-05-29T14:05:16Z2010-05-29T14:05:16ZThanks for the spelling corrections; I've incorporated them. I've also placed the authors' names in the order appearing in their paperhttp://mathoverflow.net/questions/26266/spectral-sequences-in-number-theory/26282#26282Comment by IvanIvan2010-05-28T16:32:45Z2010-05-28T16:32:45Zalso, I second Mariano's question above.http://mathoverflow.net/questions/17634/definition-of-chow-groups-over-spec-z/17659#17659Comment by IvanIvan2010-03-09T22:48:16Z2010-03-09T22:48:16ZThank you for the illuminating examples and references Prof. Liu, I am looking forward to the Gabber/Lorenzini article.http://mathoverflow.net/questions/17634/definition-of-chow-groups-over-spec-z/17652#17652Comment by IvanIvan2010-03-09T22:46:43Z2010-03-09T22:46:43ZThank you! this is just what I was looking forhttp://mathoverflow.net/questions/17634/definition-of-chow-groups-over-spec-z/17637#17637Comment by IvanIvan2010-03-09T19:26:08Z2010-03-09T19:26:08Zwhile smooth over (say) perfect fields implies regular, regularity does not imply smoothness (eg over inseparable extensions). i'm referencing the definition of smoothness (of a morphism) (EGA IV) for arbitrary schemes (not just varieties).
Here is a typical example where regular does not imply smooth: let k be an inperfect field, take a finite inseparable extension L/k, then $\mathbb{P}^1 _L$ is regular (variety over k) but not smooth over k.http://mathoverflow.net/questions/17634/definition-of-chow-groups-over-spec-z/17637#17637Comment by IvanIvan2010-03-09T18:41:43Z2010-03-09T18:41:43Zthank you, and what does "smooth scheme S" mean? (smooth is always a relative notion), bc if it means S is smooth over a field k, then it coincides with the above definition. I think the first chapter of 'Lectures on Arakelov geometry' is also a good reference, here they treat schemes over Dedekind rings (for example)http://mathoverflow.net/questions/16628/definition-of-automorphism-of-schemes-aut-x-y/16629#16629Comment by IvanIvan2010-03-02T07:13:11Z2010-03-02T07:13:11ZAlmost, but the crucial point is exactly what "isomorphism" should be. For etale covers $Y\rightarrow X$, the group $Aut(Y/X)$ is the set of <i>scheme</i> isomorphisms of $Y$ fixing $X$. It is then a consequence that IF #Aut(Y/X) = [K(Y):K(X)]$ Then we can talk about permuting geometric fibers.
I was looking, eg, for an affine explanation (imprecise), but precisely, the claims in this paper aim at something I was looking for:
<a href="http://arxiv.org/abs/0910.4646" rel="nofollow">arxiv.org/abs/0910.4646</a>http://mathoverflow.net/questions/15781/given-a-number-field-k-when-is-its-hilbert-class-field-an-abelian-extension-of/16340#16340Comment by IvanIvan2010-02-26T04:43:41Z2010-02-26T04:43:41ZThanks! explicit finite extensions was what I was looking for. In skimming the paper, it looks very well-written and with only elementary methods as you mentioned.
<a href="http://jtnb.cedram.org/item?id=JTNB_1997__9_1_51_0" rel="nofollow">jtnb.cedram.org/item?id=JTNB_1997__9_1_51_0</a>http://mathoverflow.net/questions/16331/when-does-a-projective-morphism-give-an-etale-morphism-into-affine-space-finiComment by IvanIvan2010-02-25T03:51:11Z2010-02-25T03:51:11ZThank you for the responses. Indeed, the simple example shows that the answer is negative in general; eg, etale morphisms must preserve dimension. I was curious about generalizations of noether normalization.