User john zheng - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-20T06:46:23Zhttp://mathoverflow.net/feeds/user/30985http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/120137/how-to-define-laplacian-on-l-2How to define Laplacian on $L_2$John Zheng2013-01-28T18:35:08Z2013-01-29T08:16:06Z
<p>This might be a dumb question, but I thought the Laplacian (classical) is defined for $C^2$ functions. How do we extend that to be a self-adjoint operator on all of $L_2$?
Is it the so called Friedrich's extension theorem? Is the extension explicit?
How would I, for example, compute the Laplacian of |x|</p>
<p>Thanks</p>