most recent 30 from http://mathoverflow.net 2013-05-21T10:09:02Z http://mathoverflow.net/feeds/user/2822 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/12969/non-dedekind-domain-in-which-every-ideal-is-generated-by-at-most-two-elements/13068#13068 Carl Weisman 2010-01-26T20:28:23Z 2010-01-26T20:28:23Z

<p>H. Sah was probably Chih Han Sah. Obituary: <a href="http://www.nytimes.com/1997/08/18/nyregion/chih-han-sah-62-mathematics-professor.html?pagewanted=1" rel="nofollow">http://www.nytimes.com/1997/08/18/nyregion/chih-han-sah-62-mathematics-professor.html?pagewanted=1</a></p>

http://mathoverflow.net/questions/7155/famous-mathematical-quotes/12219#12219 Carl Weisman 2010-01-18T19:03:55Z 2010-01-19T14:21:52Z

<p>And each man hears as the twilight nears, to the beat of his dying heart, the devil tap on the darkening pane, "You did it, but is it art?"</p> <p>Epigraph to Hille-Phillips, "Functional analysis and semigroups"</p>

http://mathoverflow.net/questions/9852/special-bases-of-number-fields Carl Weisman 2009-12-27T04:39:38Z 2009-12-27T13:31:12Z

<p>Let K be a number field of degree n with a fixed embedding in the complex numbers. Let | . | be the normalized absolute value given by that embedding. (The square of the ordinary absolute value if the embedding is non-real.) Does there exist a basis x_1 , ... , x_n for K over the rationals with the following property:</p> <p>| r_1 x_1 | + ... + | r_n x_n | = the maximum of | r_1 x_1 + ... + r_n x_n |_v</p> <p>where | . |_v runs through the normalized archimedean absolute values of K ? </p> <p>Later: As posed, the answer is no. Suppose I started with the field generated by a cube root and was unlucky enough to start with the real embedding. Then I'd be in effect trying to show ( x + y + z )^2 > x^3 + y^3 + z^3 on the positive octant. But if I was lucky enough to start with the complex embedding ...</p>