User sep332 - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-24T13:52:29Zhttp://mathoverflow.net/feeds/user/2576http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/13396/are-the-gell-mann-matrices-extremal-when-used-as-kraus-operators-for-a-quantum-chAre the Gell-Mann matrices extremal when used as Kraus operators for a quantum channel?sep3322010-01-29T18:39:53Z2012-05-31T13:30:06Z
<p>Landau and Streater proved that a set of Kraus operators, Ai, is extremal if and only if the set</p>
<p>$\{A_{k}^{\dagger}A_{l}\}_{k,l \ldots N}$ </p>
<p>are linearly independent. I have seen very convincing arguments both for and against. You can even see two PDFs of Mathematica notebooks "proving" <em>both</em> answers here: <a href="http://quantummoxie.wordpress.com/2010/01/28/a-quirky-mathematical-problem-in-need-of-explanation/" rel="nofollow">http://quantummoxie.wordpress.com/2010/01/28/a-quirky-mathematical-problem-in-need-of-explanation/</a></p>
<p>What is missing from these proofs?</p>
http://mathoverflow.net/questions/18375/is-there-any-finitely-long-sequence-of-digits-which-is-not-found-in-the-digits-ofIs there any finitely-long sequence of digits which is not found in the digits of pi?sep3322010-03-16T14:02:52Z2010-11-05T07:09:22Z
<p>I know it's likely that, given a finite sequence of digits, one can find that sequence in the digits of pi, but is there a proof that this is possible for all finite sequences? Or is it just very probable?</p>
http://mathoverflow.net/questions/13396/are-the-gell-mann-matrices-extremal-when-used-as-kraus-operators-for-a-quantum-chComment by sep332sep3322010-01-29T19:15:28Z2010-01-29T19:15:28Z@Jon Thanks for the LaTeX hint and the Streater correction. I will try to rephrase the question so that it makes more sense.