User johndoe - MathOverflowmost recent 30 from http://mathoverflow.net2013-06-19T20:44:47Zhttp://mathoverflow.net/feeds/user/25577http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/127841/giving-topx-y-an-appropriate-topology/127922#127922Answer by johndoe for Giving $Top(X,Y)$ an appropriate topologyjohndoe2013-04-18T06:11:24Z2013-04-19T09:24:04Z<p>It might be of interest to the original poster to know that $Top(X,Y)$ endowed with the compact-open topology guarantees at least one direction in the implication. In other words, if $F_*\colon X\times\mathbb{I}\to Y$ is continuous then $F\colon \mathbb{I}\to Top(X,Y)$ is. Hence you can safely interpret any homotopy as a path in the function space $Top(X,Y)$, but (allegedly) there are paths in $Top(X,Y)$ which do not correspond to homotopies.</p>
<p>I, for my part, would like to see a counterexample for the opposite direction, since all the counterexamples I know of seem to use a space different than $\mathbb{I}$.</p>
<p>Reference: Dugundji, Topology, Chapter XII, Theorem 3.1.</p>
http://mathoverflow.net/questions/104198/classify-mathbbrn-bundles/104203#104203Answer by johndoe for Classify $\mathbb{R}^n$-bundlesjohndoe2012-08-07T14:33:22Z2012-08-07T18:45:26Z<p>I assume that by $\mathbb{R}^n$-fiber bundles you mean differentiable bundles with fiber diffeomorphic to $\mathbb{R}^n$. So you are forgetting the linear structure of $\mathbb{R}^n$, keeping only the smooth structure. It is a fact that $\textit{Diff}(\mathbb{R}^n)$ deformation retracts to $\textit{GL}(n,\mathbb{R})$, hence yes, the classification of rank $n$ real vector bundles is essentially the same as that of $\mathbb{R}^n$-fiber bundles. I don't know whether this holds at the topological level already (that is, whether $\textit{Homeo}(\mathbb{R}^n)$ deformation retracts to $\textit{GL}(n,\mathbb{R})$).</p>
<p>EDIT: it seems that at the topological level the two beasts are different, at least for some $n$. The result is contained in a paper by William Browder entitled "Open and closed disc bundles", Ann. of Math. (2) 83 (1966), 218-230. It is freely available on JSTOR. As a consequence of the results in that paper, there exists some $n$ for which $\textit{Homeo}(\mathbb{R}^n)$ does not deformation retract onto $\textit{GL}(n,\mathbb{R})$. As far as I know, $n>2$.</p>
http://mathoverflow.net/questions/133865/does-the-gluing-procedure-in-robert-walds-book-general-relativity-yield-a-hausComment by johndoejohndoe2013-06-16T10:05:25Z2013-06-16T10:05:25Zhave you tried looking at the equivalent condition that the quotient map be open and $\sim$ be a closed subset of $\times^2\bigsqcup_{U\in\mathcal{U}}\tilde{M}_U$?http://mathoverflow.net/questions/133700/every-real-holomorphic-hamiltonian-vector-field-on-a-kahler-manifold-is-killingComment by johndoejohndoe2013-06-14T09:15:19Z2013-06-14T09:15:19Z@Yemon Choi: yes.http://mathoverflow.net/questions/133724/existence-of-geodesics-in-continuous-metricsComment by johndoejohndoe2013-06-14T09:11:49Z2013-06-14T09:11:49Zthis paper seems relevant: <a href="http://arxiv.org/abs/1212.6962" rel="nofollow">arxiv.org/abs/1212.6962</a>http://mathoverflow.net/questions/130472/monotone-homotopy/130503#130503Comment by johndoejohndoe2013-05-13T17:48:12Z2013-05-13T17:48:12ZI don't understand. How is "Directed Homotopy Theory" related to the OP question? Thanks for any clue.http://mathoverflow.net/questions/127841/giving-topx-y-an-appropriate-topology/128362#128362Comment by johndoejohndoe2013-04-23T12:51:53Z2013-04-23T12:51:53ZI am interested in the reference to Lawvere's paper, thank you in advance.http://mathoverflow.net/questions/127841/giving-topx-y-an-appropriate-topologyComment by johndoejohndoe2013-04-18T05:53:16Z2013-04-18T05:53:16Z@Amr: it seems you misplaced some * in the edited versionhttp://mathoverflow.net/questions/127841/giving-topx-y-an-appropriate-topology/127853#127853Comment by johndoejohndoe2013-04-17T17:08:14Z2013-04-17T17:08:14Zdoesn't Isbell consider the case where I (as in the OP question) might run over the whole category of spaces? In other words, it seems to me that the OP question is a special case of the problem considered in Isbell's survey and might very likely have an affirmative answer. Am I wrong?http://mathoverflow.net/questions/127841/giving-topx-y-an-appropriate-topologyComment by johndoejohndoe2013-04-17T17:03:14Z2013-04-17T17:03:14Zto Anton Fetisov: why is the case I rather useless?http://mathoverflow.net/questions/127841/giving-topx-y-an-appropriate-topology/127847#127847Comment by johndoejohndoe2013-04-17T14:10:12Z2013-04-17T14:10:12Zshouldn't A be the interval I in order to prove the inexistence of such a topology?http://mathoverflow.net/questions/121620/why-does-gln-have-no-spinor-representationsComment by johndoejohndoe2013-02-12T17:20:05Z2013-02-12T17:20:05Zi believe the missing word here is faithful. take a look at lemma 5.23 in lawson-michelsohn.http://mathoverflow.net/questions/121168/group-of-diffeomorphisms-of-a-manifoldComment by johndoejohndoe2013-02-08T10:50:13Z2013-02-08T10:50:13Zyou might want to take a look at banyaga's book "the structure of classical diffeomorphism groups", 1997.http://mathoverflow.net/questions/118955/real-symmetric-matrix-has-at-least-one-real-eigenvalue-an-elementary-algebraicComment by johndoejohndoe2013-01-15T10:16:08Z2013-01-15T10:16:08Zthis question seems a duplicate of this one <a href="http://mathoverflow.net/questions/118626/real-symmetric-matrix-has-real-eigenvalues-elementary-proof" rel="nofollow" title="real symmetric matrix has real eigenvalues elementary proof">mathoverflow.net/questions/118626/…</a> (and the OP has actually contributed to it by answering)http://mathoverflow.net/questions/116888/on-john-von-neumann-and-quantum-mechanics/116981#116981Comment by johndoejohndoe2012-12-21T18:27:43Z2012-12-21T18:27:43Ztoo much alcohol during festivities?http://mathoverflow.net/questions/108560/what-is-a-good-book-on-topological-groupsComment by johndoejohndoe2012-10-01T17:23:58Z2012-10-01T17:23:58ZYou might want to take a look at Hewitt-Ross (two volumes).http://mathoverflow.net/questions/107163/a-function-that-is-defined-everywhere-but-has-unknown-valuesComment by johndoejohndoe2012-09-14T13:06:45Z2012-09-14T13:06:45ZConsider the function that is 1 everywhere if at least one proposed example suits your tastes, and 0 everywhere if whichever suggestion comes you can always find some reason to reject it.