User roberto bosch cabrera - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-24T22:04:33Zhttp://mathoverflow.net/feeds/user/23528http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/96362/knight-tour-prime-conjectureKnight tour prime (conjecture)Roberto Bosch Cabrera2012-05-08T18:44:42Z2012-11-13T19:17:55Z
<p>Hello,</p>
<p>I have the following conjecture:</p>
<p>Write all numbers from $1$ to $n^2$ over an $n\times n$ board as usually. There not exists $n$ such that we can find a hamiltonian path on primes numbers with a knight.</p>
<p>Andres Sanchez Perez (Ecole Polytechnique, Paris, France) verified this conjecture for $3\leq n \leq 100$.</p>
<p>Any comments or reference will be appreciated.</p>
http://mathoverflow.net/questions/96292/a-hard-diophantine-equationA hard diophantine equationRoberto Bosch Cabrera2012-05-08T04:26:18Z2012-05-10T01:15:36Z
<p>Hello !</p>
<p>I would like prove that the following diophantine equation is unsolvable: $m!+27=n^3$.</p>
<p>Thanks in advance.</p>
http://mathoverflow.net/questions/96292/a-hard-diophantine-equationComment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-10T03:45:12Z2012-05-10T03:45:12Z@Mark Sapir: Thank you.http://mathoverflow.net/questions/96292/a-hard-diophantine-equationComment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-10T03:43:45Z2012-05-10T03:43:45Z@GH: Thank you, your proof is amazing.http://mathoverflow.net/questions/96362/knight-tour-prime-conjecture/96391#96391Comment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-09T02:19:28Z2012-05-09T02:19:28Z@ timur:(update)
Thank you, your argument is good, but you are considering that $3,5,7,11,13$ are intermediate or re-entry nodes for the hamiltonian path. What occurs if the path begin in $3$ for example?(similarly for $5,7,11,13$). http://mathoverflow.net/questions/96362/knight-tour-prime-conjectureComment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-08T23:43:08Z2012-05-08T23:43:08Z@Gerry Myerson: thanks for your new questions. http://mathoverflow.net/questions/96292/a-hard-diophantine-equation/96294#96294Comment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-08T23:24:07Z2012-05-08T23:24:07Z@GH: Thank you for your new Edit proving that $m<10^{12}$.http://mathoverflow.net/questions/96362/knight-tour-prime-conjecture/96366#96366Comment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-08T22:56:25Z2012-05-08T22:56:25Z@Eric Naslund: thanks a lot for your comments. The case when $n$ is odd is easy, as you noted, I'm not wrote precisely my comment to conjecture, it must be $n$ even between $4$ and $100$, I'm sorry.
Your improve to path in general is good, we need a bound for $n$ such that we can use a computer.
http://mathoverflow.net/questions/96292/a-hard-diophantine-equation/96294#96294Comment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-08T15:14:23Z2012-05-08T15:14:23ZThis problem arise (it is the hard part) when we try to solve the equation:
$x!+y!+3=Z^3$ which was proposed as $J198$ in Mathematical Reflections. I think that the solution can be found in
(1) <a href="http://www.renyi.hu/~p_erdos/1937-09.pdf" rel="nofollow">renyi.hu/~p_erdos/1937-09.pdf</a>
(2) <a href="http://www.ams.org/journals/tran/2006-358-04/S0002-9947-05-03780-3/home.html" rel="nofollow">ams.org/journals/tran/2006-358-04/…</a>
but I'm not sure. I'm trying to find an "elementary" solution.
http://mathoverflow.net/questions/96292/a-hard-diophantine-equation/96294#96294Comment by Roberto Bosch CabreraRoberto Bosch Cabrera2012-05-08T14:51:53Z2012-05-08T14:51:53ZThank you so much GH, now it is interesting find an upper bound for $m$ such that we can begin a computer search.