User sergio a. yuhjtman - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-23T09:04:11Zhttp://mathoverflow.net/feeds/user/22789http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/81780/nonseparable-disintegration-theory-references/118068#118068Answer by Sergio A. Yuhjtman for Nonseparable disintegration theory: referencesSergio A. Yuhjtman2013-01-04T17:00:16Z2013-01-04T17:00:16Z<p>In case this recent article arxiv.org/abs/1212.6192 is correct, it is surely relevant.</p>
http://mathoverflow.net/questions/113977/proper-morphisms-of-c-algebras-nondegenerate-representationsProper morphisms of C*-algebras / Nondegenerate representationsSergio A. Yuhjtman2012-11-20T18:54:17Z2012-11-29T05:10:36Z
<p>Let $A \to B$ be a proper morphism of $C^*$-algebras. A nondegenerate representation of $B$ induces a nondegenerate representation of $A$. Does the converse hold?</p>
<p>I.e.: let $A \to B$ be a morphism of $C^*$-algebras such that every nondegenerate representation of $B$ induces a nondegenerate representation of $A$. Does the morphism result proper? I guess not.</p>
http://mathoverflow.net/questions/90969/sheafification-via-hypercovers/95607#95607Answer by Sergio A. Yuhjtman for Sheafification via hypercoversSergio A. Yuhjtman2012-04-30T19:40:36Z2012-04-30T19:40:36Z<p>One way of constructing the associated sheaf in one step is written here:
<a href="http://cms.dm.uba.ar/academico/carreras/licenciatura/tesis/yuhjtman.pdf" rel="nofollow">http://cms.dm.uba.ar/academico/carreras/licenciatura/tesis/yuhjtman.pdf</a>
(in spanish) page 19, (3.2).
The key idea (due to Eduardo Dubuc) is to consider "locally compatible families" instead of just "compatible families".</p>
http://mathoverflow.net/questions/95188/weak-topology-restricted-to-the-unitary-group-of-a-von-neumann-algebraWeak topology restricted to the unitary group of a von Neumann algebraSergio A. Yuhjtman2012-04-25T19:56:47Z2012-04-25T20:14:57Z
<p>Consider the weak topology in a von Neumann algebra (weak in the sense of Banach spaces).</p>
<p>Does this topology coincide with the rest of the "weak" topologies when restricted to the unitary group?</p>
http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theoryMathematical foundations of Quantum Field Theory Sergio A. Yuhjtman2012-04-14T04:39:42Z2012-04-16T01:45:28Z
<p>Is there any reasonable approach, essentially different from Wightman's axioms and Algebraic Quantum Field Theory, aimed at obtaining rigorous models for realistic Quantum Field Theories? (such as Quantum Electrodynamics).</p>
<p>EDIT: the reason for asking "essentially different" is the following. It is possible to intuitively think "states" as solutions of the equations of motion (in some sense, in a "multiparticle space"). In realistic interacting QFT, the equations of motion are nonlinear. So, according to my chosen intuitive concept, a reasonable state space should be nonlinear (something like a Hilbert manifold). Meanwhile, in Wightman or AQFT frameworks, state spaces are Hilbert spaces. This seems to correspond with the fact that it is very very difficult to construct interacting QFT's in these frameworks. So, as a desire... there should be a different, more interaction-friendly framework where realistic models arise in a more natural way.</p>
<p>Does something in this direction already exist?</p>
http://mathoverflow.net/questions/93873/where-is-the-error-in-this-argumentWhere is the error in this argument?Sergio A. Yuhjtman2012-04-12T15:36:01Z2012-04-13T21:41:56Z
<p>Let $G$ be a locally compact Hausdorff group.
It is known that $G$ can be topologically embedded in $W^{\ast}(G)$ , its universal $W^{\ast}$-algebra (with the $\sigma$-weak topology). An element $T \in W^{\ast}(G)$ is a function assigning to each representation $\pi$ a bounded operator $T(\pi) \in B(H_{\pi})$. This $T$ must be compatible with interwiners and $T(\pi)$ must be uniformly bounded.</p>
<p>This was done (in a slightly different language) by J. Ernest here: <a href="http://www.jstor.org/stable/2373020" rel="nofollow">http://www.jstor.org/stable/2373020</a></p>
<p>Now define $G_{\otimes}= \{ T \in W^*(G)_{\neq 0} / T(\pi_1 \otimes \pi_2) = T(\pi_1) \otimes T(\pi_2) \}$</p>
<p>It's not hard to see that elements in $G_{\otimes}$ are unitaries. This is briefly proven here: <a href="http://cms.dm.uba.ar/Members/sergioyuhjtman/WG2.pdf/download" rel="nofollow">http://cms.dm.uba.ar/Members/sergioyuhjtman/WG2.pdf/download</a> (proposition 4.2).</p>
<p>Now Tatsuuma's duality theorem applies (<a href="http://projecteuclid.org/DPubS?service=UI&version=1.0&verb=Display&handle=euclid.pja/1195522200" rel="nofollow">Tatsuuma</a>, proposition 2) so $G=G_\otimes$. But $G_\otimes$ is closed and inside the unit ball, so it is compact (always $\sigma$-weak topolgy). Therefore $G$ is compact. </p>
http://mathoverflow.net/questions/93681/are-the-categories-of-representations-of-g-and-cg-isomorphicAre the categories of representations of G and C*(G) isomorphic?Sergio A. Yuhjtman2012-04-10T16:39:39Z2012-04-11T13:27:32Z
<p>Let G be a locally compact Hausdorff group, and C*(G) the full group C* algebra.</p>
<p>I found in some books that "representation theory of both is the same". Can this be expressed as "the categories are equal"?</p>
<p>(Here "representation of G" means a unitary weakly continuous representation on a Hilbert space, and representations of C*(G) are nondegenerate. Morphisms in those categories are the interwiner bounded operators).</p>
http://mathoverflow.net/questions/113977/proper-morphisms-of-c-algebras-nondegenerate-representations/114547#114547Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-11-29T18:06:09Z2012-11-29T18:06:09ZThanks a lot! .http://mathoverflow.net/questions/113977/proper-morphisms-of-c-algebras-nondegenerate-representationsComment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-11-21T18:16:28Z2012-11-21T18:16:28ZIt is a morphism that maps an approximate unit to an approximate unit (equivalently: it maps every approximate unit to an approximate unit).http://mathoverflow.net/questions/58752/approximate-units-from-strictly-positive-elements-in-c-algebrasComment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-11-05T23:41:54Z2012-11-05T23:41:54ZDoes anyone have a reference for this equivalence? Thanks...http://mathoverflow.net/questions/90969/sheafification-via-hypercovers/95607#95607Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-30T21:10:03Z2012-04-30T21:10:03ZThis proof has no surprising ideas other than the definition of "locally compatible families". From there it is like the usual ++ construction. I'm not familiar with the hypercovers approach.http://mathoverflow.net/questions/95579/sheafification-why-does-twice-sufficeComment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-30T19:29:49Z2012-04-30T19:29:49ZIt is possible to construct the associated sheaf functor in only one step. This is due to Eduardo Dubuc. The key idea is to consider "locally compatible families" instead of "compatible families". You can read the details here: <a href="http://cms.dm.uba.ar/academico/carreras/licenciatura/tesis/yuhjtman.pdf" rel="nofollow">cms.dm.uba.ar/academico/carreras/licenciatura/…</a> (spanish, sorry) Page 19, (3.2).http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theory/94124#94124Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-18T16:54:36Z2012-04-18T16:54:36ZInteresting. Where can I find a good rigorous treatment of the anharmonic oscillator? (as simple as possible, of course)http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theory/94124#94124Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-17T05:41:48Z2012-04-17T05:41:48ZFor the hydrogen atom, double-well, etc, (i.e: one non-relativistic quantum particle) the interaction seem to be of a different nature than in QFT, because it is external. The object interacting with the particle is outside the model! Could this be the origin of difficulties in order to obtain rigorous models? Why the mathematical apparatus should be necessarily essentially the same?http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theory/94124#94124Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-17T05:29:56Z2012-04-17T05:29:56ZOK. So the equations of motion in QFT apply to the fields and not the states.http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theory/94124#94124Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-15T16:23:29Z2012-04-15T16:23:29ZAccording to what I know, Schroedinger and Heisenberg picture are trivially equivalent. However, you say that the hydrogen atom and double-well have "non-linear (Heisenberg) equations of motion that live perfectly...". I would like to know about those nonlinear equations. Any reference?http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theory/94124#94124Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-15T16:16:35Z2012-04-15T16:16:35ZSchroedinger equation for the Hydrogen atom and double well is a linear PDE. So I still don't see a valid objection.
"In short, the standard approaches to constructive QFT already incorporate non-linear interactions in a natural way." I disagree.http://mathoverflow.net/questions/94014/mathematical-foundations-of-quantum-field-theoryComment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-14T04:57:21Z2012-04-14T04:57:21ZI didn't find it between the 52 tagged as qft.http://mathoverflow.net/questions/93873/where-is-the-error-in-this-argument/93941#93941Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-14T01:28:58Z2012-04-14T01:28:58ZOK, I'll accept the answer to be polite and grateful (actually I want to thank everyone who got involved!) but I still think as before.http://mathoverflow.net/questions/93873/where-is-the-error-in-this-argument/93941#93941Comment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-13T15:33:02Z2012-04-13T15:33:02ZThis is a good reference, thank you! But the real answer is what Jesse Peterson said.http://mathoverflow.net/questions/93873/where-is-the-error-in-this-argumentComment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-13T03:28:00Z2012-04-13T03:28:00ZThank you! That sounds right. I will check it.http://mathoverflow.net/questions/93873/where-is-the-error-in-this-argumentComment by Sergio A. YuhjtmanSergio A. Yuhjtman2012-04-12T19:44:54Z2012-04-12T19:44:54ZI think this is wrong: "it suffices to describe an element $T$ of $G_\otimes$ on irreducibles" because $T$ might not commute with direct integrals. However, in case Tatsuuma is wrong, it is still possible to reach a contradiction. Thit is explained here: <a href="http://cms.dm.uba.ar/Members/sergioyuhjtman/WG2.pdf/download" rel="nofollow">cms.dm.uba.ar/Members/sergioyuhjtman/WG2.pdf/…</a>