User spaghetti inks - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-21T09:40:31Zhttp://mathoverflow.net/feeds/user/19595http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/82131/the-shafarevich-conjecture-and-motivic-langlands-stacksThe Shafarevich Conjecture and motivic Langlands stacks.Spaghetti Inks2011-11-29T01:40:07Z2011-11-29T01:40:07Z
<p>Hi, I recently learned about an amazing conjecture of Shafarevich
(proved by Faltings) about the finiteness of the number
of curves of a fixed genus with good reduction outside a
finite number of primes. Moreover, there are no curves
of genus $> 0$ at all with good reduction everywhere (Abrashkin/Fontaine).</p>
<p>Is there an analog of this theorem for
stacks (of the type described below), and how does this connect
to the Langlands program?</p>
<p>From what I understand, the moduli space
$\mathcal{M}_{1,1}$ of elliptic curves
can be thought of a stack with good reduction everywhere
over $\mathbb{Z}$. (Mumford computed that the
Picard group of this stack is $\mathbf{Z}/12\mathbf{Z}$.)
Moreover, the generic
fiber of this stack of the form
$[X/G]$, where $X/\mathbf{Q}$
is a smooth proper curve and $G$ is a finite group.
I want to restrict attention to exactly this special class of stacks (do they have a name?).</p>
<p>First question: can one classify smooth proper stacks $\mathcal{X}$
over $\mathbf{Z}$ with generic fiber $[X/G]$ for some smooth
proper curve $X$ over $\mathbf{Q}$ and finite group $G$? Are there finitely
many such stacks?
Is $\mathcal{M}_{1,1}$ the only one with negative euler characteristic?</p>
<p>Second question: are there finitely many smooth stacks
$\mathcal{X}$ over $\mathbf{Z}[1/N]$ where $N$ and
$\chi(\mathcal{X})$ are fixed?</p>
<p>Finally, is there any Tannakian/Langlands/Motivic formulism
that attaches some motivic type object to $\mathcal{M}_{1,1}$
that isn't just the "trivial" motive attached to $\mathbf{P}^1$?</p>
<p>Apologies for any vagueness in this question, hopefully a
more seasoned MO Langlands pro like David Hansen or James Taylor can help me out.</p>
http://mathoverflow.net/questions/82131/the-shafarevich-conjecture-and-motivic-langlands-stacksComment by Spaghetti InksSpaghetti Inks2011-11-30T04:49:38Z2011-11-30T04:49:38ZNaturally $X/k$ is the notation, I say to old Qfwfq, what else could it have been?http://mathoverflow.net/questions/82131/the-shafarevich-conjecture-and-motivic-langlands-stacksComment by Spaghetti InksSpaghetti Inks2011-11-30T04:48:03Z2011-11-30T04:48:03ZDear Professor Carnahan, I would love it if you could explain the construction ("it is not too difficult to make genus zero curves with .. good reudction everywhere").http://mathoverflow.net/questions/82131/the-shafarevich-conjecture-and-motivic-langlands-stacksComment by Spaghetti InksSpaghetti Inks2011-11-29T04:10:17Z2011-11-29T04:10:17ZDear Professor Dalawat - thanks for the links! This is addressing the last question I presume? If I understand you, you are saying that the "1-motive" should be an abelian variety over $\mathbf{Z}$ which can't exist.
But I was thinking along the following lines: is there some integral "Motivic like" object $[\mathcal{M}]$ for which
"$H^1$" returned $\mathbf{Z}/\mathbf{Z}12$. I don't even know if Motives are supposed to form a category with "integral" properties... and maybe this is related to "torsion" automorphic forms...
perhaps your remarks merely expose my ignorance, but I like to dream!