User van abel - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-26T05:54:30Zhttp://mathoverflow.net/feeds/user/18801http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/89061/whats-the-relationship-between-the-riemannian-metric-and-jacobi-fieldWhat's the relationship between the riemannian metric and Jacobi field?van abel2012-02-21T00:37:10Z2012-02-21T13:59:11Z
<p>I encounter to the question in reading the following Excise:</p>
<blockquote>
<p>Let $(M,g)$ be a $m$-dimensional Riemannian manifold, and $(r,\theta^1,\theta^2,\ldots,\theta^{m-1})$ be the (geodesic) polar coordinate. Prove that, if $M$ is a space form, i.e., with the constant (sectional) curvature $K$, then $g$ has the following expression (by Gauss's Lemma):
$$
\newcommand{\rd}{\mathrm d}
\rd s^2=(\rd r)^2+(f(r))^2h_{ij}(\theta)\rd\theta^i\rd\theta^j,
$$
where the $m-1$-dimensional metric $(\rd\sigma)^2=h_{ij}(\theta)\rd\theta^i\rd\theta^j$ has constant sectional curvature $1$, and
$$
f(r)=\begin{cases}
\sin(\sqrt{Kr^2})/\sqrt{K},&\text{if }K>0;
r,&\text{if }K=0;
\sinh(\sqrt{-Kr^2})/\sqrt{-K},&\text{if }K<0.
\end{cases}
$$</p>
</blockquote>
<p>I already know that the Jacobo-field $J$ ($J(0)=0$, $|\dot J(0)|=1$ and $J$ is perpendicular to the base geodesic curve $\gamma(t)$) for manifold with constant sectional curvature $K$ is
$$
J(t)=f(t)W(t),
$$
where $f(t)$ is defined as above and $W(t)$ is a unit parallel vector filed along $\gamma$ with $W(t)\bot\dot\gamma(t)=T(t)$.</p>
<p>So my question is that: can we give a proof that based on the Jacobi-field? If not, what's the relation between the two problem?</p>
<p>In fact, I don't know how the solve the first problem, and try to use Jacobi-field to give a proof without no results.</p>
http://mathoverflow.net/questions/79464/perpendicular-in-conformal-disk-modelPerpendicular in conformal disk modelvan abel2011-10-29T13:41:19Z2011-10-30T03:45:13Z
<p>In Euclidean Geometry, we know that from a given point there is an unique line perpendicular to a given line. In conformal disk model, can we do the same thing? Or, more exactly, did there exists such a (geodesic) line, if exists, are they unique? if not, when?</p>
<p><img src="http://www.freeimagehosting.net/newuploads/21264.jpg" alt="Figure"></p>
<p>in the above figure, <strong>disk A</strong> is the conformal model disk. <strong>J</strong> is the given point, and <strong>CD</strong> is the given line; I asked how to get the line <strong>GF</strong>, such that <strong>J</strong> is on it and <strong>GF</strong> perpendicular to <strong>CD</strong>.</p>
http://mathoverflow.net/questions/79167/is-there-a-similar-formula-in-spherical-and-hyperbolic-geometry-as-euclidean-geomIs there a similar formula in spherical and hyperbolic geometry as Euclidean Geometry?van abel2011-10-26T15:14:14Z2011-10-26T22:42:55Z
<ol>
<li><p>In an Euclidean plane, we know that the area of a triangle is determined by the length of base and the height, i.e.,
$$
S_{\Delta}=\frac{1}{2}a.h,
$$
where $a$ is the length of base and the $h$ is the height. Is there a similar formula in Spherical and hyperbolic spaces?</p></li>
<li><p>In Euclidean plane, we know that the cosine law says that (suppose $\alpha$, $\beta$, $\gamma$ are the angles, and $a, b, c$ are the lengths opposite $a, b, c$ respectively.)
$$
\cos\gamma=\frac{a^2+b^2-c^2}{2ab}.
$$
Then is there a analogue in spherical and hyperbolic geometry? I have noted that the First and Second Cosine law are not so clearly relevant with this formula.</p></li>
</ol>
http://mathoverflow.net/questions/103956/did-the-real-number-system-uniqueComment by van abelvan abel2012-08-06T02:50:14Z2012-08-06T02:50:14ZThanks for Yuan's comments, maybe my definition of real fields are not correctly for my question, and maybe the definition should be: A <em>ordered</em> field $R$ is called real field, if ...http://mathoverflow.net/questions/89061/whats-the-relationship-between-the-riemannian-metric-and-jacobi-fieldComment by van abelvan abel2012-02-22T11:54:08Z2012-02-22T11:54:08ZThanks for all the above suggestions. At first, I just suspected that there would be a solution by using the Jacobi fields (which was comformed by Deane Yang), believing that it should be more efficient, I just stop here, do not want to have a try by the definition of section curvature. This maybe a problem for me, especially, as a beginner. Now, I realize that, sometimes the clumsy caculation is necessary. Of course, I will have a try right now, and wish that I will work it out before exhausting my effort.http://mathoverflow.net/questions/89061/whats-the-relationship-between-the-riemannian-metric-and-jacobi-fieldComment by van abelvan abel2012-02-21T00:41:48Z2012-02-21T00:41:48ZThis question is firstly post on StackExchange:<a href="http://math.stackexchange.com/questions/111504/whats-the-relationship-between-the-riemannian-metric-and-jacobi-field" rel="nofollow" title="whats the relationship between the riemannian metric and jacobi field">math.stackexchange.com/questions/111504/…</a>, after I read the site meta, I think is more prefer to post it here.http://mathoverflow.net/questions/79464/perpendicular-in-conformal-disk-modelComment by van abelvan abel2011-10-30T03:56:48Z2011-10-30T03:56:48Zthe question continued at [link stackexchange][2].
[2]: <a href="http://math.stackexchange.com/questions/77084/perpendicular-in-conformal-disk-model" rel="nofollow" title="perpendicular in conformal disk model">math.stackexchange.com/questions/77084/…</a>http://mathoverflow.net/questions/79464/perpendicular-in-conformal-disk-modelComment by van abelvan abel2011-10-29T13:43:53Z2011-10-29T13:43:53ZMay I ask why I can't use the <b>img tag</b> in my question?http://mathoverflow.net/questions/79167/is-there-a-similar-formula-in-spherical-and-hyperbolic-geometry-as-euclidean-geomComment by van abelvan abel2011-10-27T03:02:38Z2011-10-27T03:02:38ZThanks, That is reasonable, I will do that in my following questions.http://mathoverflow.net/questions/79167/is-there-a-similar-formula-in-spherical-and-hyperbolic-geometry-as-euclidean-geomComment by van abelvan abel2011-10-26T16:10:31Z2011-10-26T16:10:31ZIs that illegal to a same question on two site?
if it is, I owe an apologize.