User anonymous - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-18T17:29:18Zhttp://mathoverflow.net/feeds/user/11304http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/48246/recursive-non-well-orders-that-are-sneaky-but-not-that-sneakyRecursive Non-Well-Orders that are Sneaky, but not THAT Sneaky.anonymous2010-12-04T04:31:02Z2010-12-04T04:31:02Z
<p>This is a variant on
<a href="http://mathoverflow.net/questions/30633/sneaky-recursive-non-well-orders" rel="nofollow">http://mathoverflow.net/questions/30633/sneaky-recursive-non-well-orders</a>
where it was asked</p>
<blockquote>
<p>Is there a recursive function $f$ such that whenever $a\in\mathcal{O}$, $f(a)$ is a Turing index for a linear non-well-order with no $H_a$ -computable descending chain?</p>
</blockquote>
<p>The answer to the original question gave a single non-well-order with no hyperarithmetic descending chain at all. Instead can $f(a)$ be a non-well-order with an $H_a$-computable descending chain but no $H_b$-computable descending chain for $b <_{\mathcal{O}} a$ ? </p>